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For finding the oxidation state of metal atom in coordination compound, charge on the ligand should be known. Chloro ligand has -1 charge. amino ligand is neutral. [MnCl2(NH3)41* Let x is the oxidation state of metal. Above compound has +1 charge on it x+2(-1)+4(0) = 1 x - 2+0 = 1 x=1+2= 3 So, oxidation of Mn metal = 3 (Co(CN)4(H20)2]2- x+4(-1) + 2(0) = -2 x= -2 + 4 = 2 Oxidation state of Co metal = 2 [Fe(OH)sCO]3- x+ 5(-1) +0 = -3 x - 5 = -3 x = -3 +5= 2 So, oxidation state of Fe metal = 2

For finding the oxidation state of metal atom in coordination compound, charge on the ligand should be known. Chloro ligand has -1 charge. amino ligand is neutral. [MnCl2(NH3)41* Let x is the oxidation state of metal. Above compound has +1 charge on it x+2(-1)+4(0) = 1 x - 2+0 = 1 x=1+2= 3 So, oxidation of Mn metal = 3 (Co(CN)4(H20)2]2- x+4(-1) + 2(0) = -2 x= -2 + 4 = 2 Oxidation state of Co metal = 2 [Fe(OH)sCO]3- x+ 5(-1) +0 = -3 x - 5 = -3 x = -3 +5= 2 So, oxidation state of Fe metal = 2

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter8: Bonding In Transition Metal Compounds And Coordination Complexes
Section: Chapter Questions
Problem 66AP
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For finding the oxidation state of metal atom in coordination compound, charge on the ligand should be known. Chloro ligand has -1 charge. amino ligand is neutral. [MnCl2(NH3)4]* Let x is the oxidation state of metal. Above compound has +1 charge on it x+2(-1)+4(0) = 1 x-2+0=1 x =1+2= 3 So, oxidation of Mn metal = 3 [Co(CN)4(H20)2]²- x+ 4(-1) + 2(0) = -2 x= -2 +4 = 2 Oxidation state of Co metal = 2 [Fe(OH)sCO]3- x+5(-1) + 0 = -3 x - 5 = -3 x= -3 +5= 2 So, oxidation state of Fe metal = 2
Transcribed Image Text:For finding the oxidation state of metal atom in coordination compound, charge on the ligand should be known. Chloro ligand has -1 charge. amino ligand is neutral. [MnCl2(NH3)4]* Let x is the oxidation state of metal. Above compound has +1 charge on it x+2(-1)+4(0) = 1 x-2+0=1 x =1+2= 3 So, oxidation of Mn metal = 3 [Co(CN)4(H20)2]²- x+ 4(-1) + 2(0) = -2 x= -2 +4 = 2 Oxidation state of Co metal = 2 [Fe(OH)sCO]3- x+5(-1) + 0 = -3 x - 5 = -3 x= -3 +5= 2 So, oxidation state of Fe metal = 2
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