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- Can you help me fix my code because the total sum per item does not show in the receipt and when choosing to perform another transaction, the input for the customer's name and the number of items overlaps as seen in the image below. package cashier; import java.util.Scanner; class List { Scanner sc = new Scanner(System.in);private String name;private int item;private int[] des;private double price;private int[] quan;private double total;private double sum; public List(String name, int item, int[] des, double total, int[] quan, double sum) {this.name = name;this.item = item;this.des = des;this.quan = quan;this.total = total;this.sum = sum;}public void Input() {System.out.print("\n Enter name of customer: ");name = sc.nextLine();System.out.print(" Enter number of items: ");item = sc.nextInt();des = new int[item];quan = new int[item];total = 0; for (int i = 0; i < item; i++) {System.out.print("\n Enter item code: ");des[i] = sc.nextInt();for (int j = 0; j < item; j++) {if…I am stuck and I could use some help this is what I have so far from the imege void writeEmpToFile(Employee *emp, FILE *f) { fwrite(&emp->salary, sizeof(emp->salary), 1, f); fwrite(&emp->yearBorn, sizeof(emp->yearBorn), 1, f); fwrite(emp->ssn, sizeof(char), SSN_SIZE, f); int len = strlen(emp->name) + 1; fwrite(&len, sizeof(int), 1, f); fwrite(emp->name, sizeof(char), len, f); } I have started working on the code and making the changes from the image as you can see that I've already started working on these steps at the very end of the code in the link but I don't know how to move forward with it Please Implement your changes into the code I have provided in the link below [This is the link to what I have so far] https://onlinegdb.com/nWSAIx8hCnINT_MIN = -32767 def cut_rod(price): """ Returns the best obtainable price for a rod of length n and price[] as prices of different pieces """ n = len(price) val = [0]*(n+1) # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val return val[n] # Driver program to test above functionsarr = [1, 5, 8, 9, 10, 17, 17, 20].
- Implement the function below. void swap(int pos1, int pos2){} Initial code to be completed: class ArrayList : public List { int* array; int index; int capacity; void dyn_all_add(){ int cap = ceil(capacity * 1.5); array = (int*)realloc(array,cap * sizeof(int)); capacity = cap; } void dyn_all_rem(){ int cap = capacity - (capacity/3); array = (int*)realloc(array,cap * sizeof(int)); capacity = cap; } public: // CONSTRUCTOR ArrayList() { capacity = 4; array = (int*)malloc(capacity); index = 0; } int add(int num) { if (index == capacity){ dyn_all_add(); } *(array + index) = num; index++; return index; } int get(int pos){ if (pos-1 < index){ return *(array + pos-1); } return -1; } int size(){ return index; }…I am having a hard time understanding the output of this program with shadow and deep binding. Can someone explain it more in detail? I posted the answers below x : integer – – globalprocedure set x(n : integer)x := nprocedure print x()write integer(x)procedure foo(S, P : function; n : integer)x : integer := 5if n in {1, 3}set x(n)elseS(n)174 Chapter 3 Names, Scopes, and Bindingsif n in {1, 2}print x()elsePset x(0); foo(set x, print x, 1); print x()set x(0); foo(set x, print x, 2); print x()set x(0); foo(set x, print x, 3); print x()set x(0); foo(set x, print x, 4); print x() Here are the answers to the questions. The program prints = 10 20 30 40 with shallow binding The program prints = 10 52 00 44 with deep binding,do some changes in code and make it unique #include <stdio.h>#include <stdlib.h>#include<string.h>//declaring functionsvoid firstFit(int [], int , int [],int );void bestFit(int [], int , int [],int );void worstFit(int [], int , int [],int );//starting programint main() {//declare partitions and processint partitions [] = {110, 450, 100, 250, 500};int processes [] = {212, 417, 112, 426};//getting their sizesint size_partitions = sizeof(partitions )/sizeof(partitions [0]);int size_processes = sizeof(processes )/sizeof(processes [0]);printf("Partitions size: ") ;for (int i=0; i<size_partitions; i++){printf("%d\t" ,partitions[i] );}//index partprintf("\nPartitions index: " );for (int i=0; i<size_partitions; i++){printf("%d\t" ,(i+1)) ;}printf( "\n" );// calling functionsfirstFit(partitions , size_partitions, processes , size_processes);bestFit(partitions , size_partitions, processes , size_processes);worstFit(partitions , size_partitions, processes ,…
- Describe what problem occurs in the following code. What modifications should be made to it to eliminate the problem? int[] sums = {6, 12, 3, 32, 12, 10, 9, 6}; for (int index = 1; index <= sums.length; index += 1) { System.out.println(sums[index]); }Write a program named Search.java that uses a function called search_string to check whether a string exists in the array or not. 1- The array of strings is iterated using a for loop and the value at every index is compared with the value to be searched in the array. 2- A boolean variable is set if any array value matches with the string. 3- At the end of the loop, this boolean variable is checked to determine if the array contains the string. Hint: You may need to import java.util.Arrays then use Arrays.toString, String equals(). The ouput should look like what is pictured below. Please provide an editable code that is easy to copy and paste.Consider the following C++ code fragment: int a = 3; int b = 2; double r = a/b; Suppose we want r to have the value 1.5, rather than 1. Which cast operator can be used in the third line to achieve this effect? a. static cast b. dynamic cast c. reinterpret cast d. none of the above
- TODO 1 Obtain all the indexes with labels equal 2 with np.where and the label array y. Keep the results in two_class_idx also index np.where() at 0 # TODO 1.1 two_class_idx = print(f"two_class_idx output: \n {two_class_idx}") try: print(f"two_class_idx shape: {two_class_idx.shape}") except Exception: pass todo_check([ (isinstance(two_class_idx, np.ndarray),f'two_class_idx is not an NumPy array! two_class_idx is currently a {type(two_class_idx)}'), (np.all(two_class_idx == np.array([3,9,11,12,16])),'two_class_idx does not contain the correct location values') ])Im facing problem with this code. #include<stdio.h> #include<math.h> void putnqueen(int); int okqueen(int, int); int setqueen(int); void queen(); char p[10][10]; int n; int main() { int a, b; clrscr(); printf(" Enter the no. of queens : "); scanf("%d", &n); for (a = 0; a < n; ++a) for (b = 0; b < n; ++b) p[a][b] = '.'; putnqueen(0); getch(); return (0); } void putnqueen(int x) { int a; if (x < n) { for (a = 0; a < n; ++a) { if (okqueen(x, a)) { p[x][a] = 'Q'; putnqueen(x + 1); p[x][a] = '.'; } } } else { printf("\n The solution is "); queen();…Can you just give a comment in short on what is this about . Or just give a comment on how dose it run. #include #define MAX_EMP 5 #include "employee.h" int count = 0; struct Employee emp[MAX_EMP]; void display() { printf("\n---=== EMPLOYEE DATA ===---\n"); printf("EMP ID\tEMP AGE\tEMP SALARY\n"); printf("======\t=======\t==========\n"); for(int i = 0; i < count; i++) { printf("%d\t%d\t%.2f\n", emp[i].id, emp[i].age, emp[i].salary); } } void add() { if(count == MAX_EMP) { printf("\nERROR!!! Maximum Number of Employees Reached\n"); return; } printf("\nAdding Employee ===============\n"); printf("Enter Employee ID: "); scanf("%d", &emp[count].id); printf("Enter Employee Age: "); scanf("%d", &emp[count].age); printf("Enter Employee Salary: "); scanf("%f", &emp[count].salary); count++; } void update() { int id, found = 0; float newSalary; printf("\nUpdate Employee Salary…