For spectrophometric method to be viable, which of the following must be met? a. A high MW complex must be produced in the reaction b. Analyte must have high absorptivity c. Species must emit light d. A complex with intense color must be produced
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For spectrophometric method to be viable, which of the following must be met?
a. A high MW complex must be produced in the reaction
b. Analyte must have high absorptivity
c. Species must emit light
d. A complex with intense color must be produced
Step by step
Solved in 2 steps
- The accompanying data (1.00-cm cells) were obtained for the spectrophotometric titration 10.00 mL of Pd(II) with 2.44 10-4 M Nitroso R(O. W Rollins and M. M. Oldham, Anal. chem .,1971, 43, 262, DOI: 10.1021/ac60297a026). Calculate the concentration of the Pd(II) solution, given that the ligand-to-cation ratio in the colored product is 2:1Graphite furnace atomizers are renowned in Atomic Absorption Spectrometry for their exceptionally low detection limits (10-12 g and lower for many elements). Why are detectabilities so much better with graphite furnaces than with flame atom cells in AAS?Analysis of ammonia via Nesslerization is based on measuring the absorbance at 420 nm of a yellowish complex formed between HgI42- and ammonia following the reaction below: 2[???4]2− + ??3 + 3??− → ??2???2? + 7?− + 2?2O Using a 1.00 cm cell, the absorbance of a reagent blank is 0.099, the absorbance of a 0.060 mM standard is 0.223. A 5.00 mL aliquote from a 1.00 L sample was reacted with Nessler reagent and diluted to 10.0 mL. The resulting solution had an absorbance of 0.685.
- Nickel bis-dimethylglyoximate complex was deposited with a weight of (4.869g) with the filter paper from the base medium from adding (10ml) of hot DMG to a salt of nickel chloride at weight (0.78g), find the percentage of nickel ion. Note that the weight of the filter paper (1.30g). At.Wt.: Ni= 58.69 g/mol, C= 12 g/mol, O=16 g/mol, H=1 g/mol, N=14 g/mol1. Instead of using an electrode to collect ions, why electron multiplier is needed as the detector for MS? 2. Discuss the role and advantage(s) of Full scan, selected ion monitoring, and MS/MS modes in chemical analysis. 3. Discuss how EI generates molecular ion and fragment ions. 4. Discuss how Positive CI and Negative CI form ions in MS. 5. Different from GCMS, why is an interface needed when coupling HPLC with MS?A 50.0-mL sample containing Ni21 was treated with 25.0 mL of 0.050 0 M EDTA to complex all the Ni21 and leave excess EDTA in solution. How many millimoles of EDTA are contained in 25.0 mL of 0.050 0 M EDTA?
- The ESI mass spectrum (positive mode) of the complexshown below contained a peak envelope with m/z527.9 (100%), 528.9 (15%), 529.9 (46%), 530.9(7%), 531.9 (0.5%). A group of peaks of lowintensity and with spacings of m/z ¼ 1 was alsoobserved around m/z 994. (a) What is the oxidationstate of Cu in the complex? (b) Assign the majorpeak and account for the isotope pattern. (c) Suggesthow the minor peak arises. [The mass spectrum of the complex complex is shown on pic.]Please help me fill the remaining spaces. The spaces marked with NA don't need to be calculate. Name Molecular Weight Amounts used mmol Equivalents M.P or BP (C) Density (g/mL) Indene 116.16 .5mL MP=-2 BP=181-182 .996 Borane-tetrahydrofuran Complex 85.94 2.8mL 1 MP= -108 BP=66 NA 30% Hydrogen Peroxide 34.01 1mL MP= -33 BP=108 NA 3 M NaOH(aq) 40 .7mL MP=318 BP=1390 NA Diethyl Ether 74.12 NA NA NA BP=75-78 .902 Hexanes 86.17 NA NA NA BP=65.5-68.3 .659 Potassium Permanganate 158.03 NA NA NA BP=100 1.0 1-Indanol (Product) 134.13 NA MP=50-54 NA 2-Indanol (Product) Same as Above Same as Above Same as Above NA MP=68-71 NA1. Name the ionization techniques for solid and liquid samples. 2. Discuss the advantage of high resolving power and mass accuracy in chemical analysis using MS. 3. Why SIM can give higher sensitivity as compared to full scan? 4. What is the advantage of MS/MS as compared with SIM?
- To measure the iron content of runoff from a ranch a 25.0 mL sample of run off was acidified with HNO3 and treated with excess KSCN to form a red complex. (KSCN itself is colorless.) The solution was then diluted to 100 mL and put into a variable pathlenght cell. For comparison, a 10.0 mL reference sample of 6.80 x 10-4 M Fe3+ was treated with HNO3 and KSCN and diluted to 50.0 mL. The reference was placed in a cell with a 1.00 cm pathlenght. The runoff had the same absorbance as the reference when the pathlenght of the runoff cell was 2.48 cm. What wa the concentraton of iron in the runoff?. A student collects the following data for the absorbance of a complex measured in 1.00 cmspectrophotometric cells. The molar absorptivity (ε) of the complex under investigation is 2.25×103L/mol·cm. Calculate the concentration of the complex in solution at each time of the reaction.Time (min)MeasuredAbsorbanceComplex Concentration(M)0.000 1.50010.000 1.31320.000 1.12530.000 0.93840.000 0.750A green solution containing Ni+2 ions absorbs 580 nm light. Undiluted, a sample of this solution sampled in a 1.00 cm diameter cuvette has an absorbance of 0.9765 a.u.. If the molar absorptivity coefficient for Ni+2 is 6.3 x 104 M -1 cm -1 at 580 nm, how much of the original stock Ni+2 solution (in mL) needs to be added to water to create a total dilute solution volume of 10.00 mL that measures an absorbance of 0.146 a.u. at 580 nm? Report your answer to 3 significant figures. Do not include the "mL' unit label in your response
