For the below balanced star-connected network of equal resistances at 50 Hz, if the Wattmeter reading is 5 kW and ammeter reading is 25 Arms, the power factor value and type, resistance and inductance are respectively ......... RO W 400 V BO Select one: O 0.5 leading, 10 Ohms, 0.01H O 0.4 lagging, 8 Ohms, 0.02H O 1, 5 Ohms, 0.1H O 0.866 lagging, 8 Ohms, 0.0147 H O 0.866 lagging, 8 Ohms, 0.02 H X

For the below balanced star-connected network of equal resistances at 50 Hz, if the Wattmeter reading is 5 kW and ammeter reading is 25 Arms, the power factor value and type, resistance and inductance are respectively ......... RO W 400 V BO Select one: O 0.5 leading, 10 Ohms, 0.01H O 0.4 lagging, 8 Ohms, 0.02H O 1, 5 Ohms, 0.1H O 0.866 lagging, 8 Ohms, 0.0147 H O 0.866 lagging, 8 Ohms, 0.02 H X

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.23P: A single-phase source has a terminal voltage V=1200volts and a currentI=1530, which leaves the...

See similar textbooks

Similar questions

There are two loads connected in parallel and powered from a 7200-V source. The first load is 50-kVA at 0.9 power factor lagging, and the second load is 45-kW at 0.85 power factor lagging. Determine the kind of KVAR and capacitance required to correct the overall power factor to 0.96 lagging.
A voltage of 200 253"8' is applied across to impedances in parallel. The values of impedances are (12+j1k) and (10-j20). Determine the KVA, KVAR, and KW in each branch and the power factor of the whole circuit.
The actual impedance of a load is 10 OHM. The new per-unit impedance of the load is 0.5 pu when Base Voltage is 200 V and Base Power is O 4000 VA O 8000 VA O 6000 VA O 2000 VA
5. The figure below shows two star connected loads with three phase power. The voltage source is 120Z0°. The loads are Z₁ = 10 + j4 № and Z₂ = 2 +j3 №. The cables are negligible. Calculate: a) the line and phase current. b) the real power from the source. c) the reactive power of the circuit. Is V N Z₁ Z₁ Z₁ Z₂ Z₂ N N Z₂
15) Kirchhoff's Voltage Law (KVL) states that A) the product of the phasor voltages around any closed path must equal zero. B) the sum of the phasor voltages around any closed path does not have to equal zero. C) the sum of the phasor voltages around any closed path must equal zero. D) the sum of the phasor voltages around a closed path cannot include "through the air."
The values of the elements for the given circuit are given below.What is the maximum average power that can be transferred to the ZL load?R1 = 400 OhmsL = 500j OhmsR2 = 100 Ohms
Two impedances consist of resistance of (15 ohms and series connectedinductance of 0.04 henry) and (resistance of 10 ohms, inductance of 0.1 henryand a capacitance of 100 microfarad, all in series) are connected in series andare connected to 230 volts, 50 – Hz AC source. Find: (a) current drawn, (b) voltageacross each impedance, (c) individual and total power factor. Draw the phasordiagram.
A resistance of 20 Ω, an inductance of 0.2H and a capacitance of 100μF are connected in series across 220-V 50 Hz mains. Determine the following: a) impedance b) current c) voltage across R, L, and C d) power in watts and VA e) power factor and angle of lag.
A star connected three phase alternator supplies power to a delta connected resistive load. The alternator has a line voltage of 480V. Each resistor of delta load has 8 ohm of resistance. Find the following values. Line voltage of the load (VL(load)) Phase voltage of the load (VP(load)) Phase current of the load (IP(load)) Line current delivered by the alternator (IL(alt)) Phase current of the alternator (IP(Alt)) Phase voltage of the alternator (VP(Alt)) True power
The circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three-phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and IT
The circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three- phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and IT RO- SO TO IR Is IT U₁-380 V CARGA 1 P₁ =950 W cos p1=0,5 ind. CARGA 2 P₂=1.140 W cos p₂=1 CARGA 3 P3=760 W cos p3=0,5 cap.
Three single phase loads are connected to the 400 V, three phase lines, 60 Hz. Load 1 operating at 3 kVA, 0.8 power factor lagging and is connected at line "a" and "b", Load 2 is a 5 kW heater and is connected at line "b" and "c", Load 3 is 4.5 kW machine that operates at a power factor of 0.6 lagging and is connected at lines "c" and "a". a. What are the line currents Ia, Ib, and Ic in Amperes (in Polar form) b. What is the total power factor.