For the circuit shown, the capacitor C, has a capacitance of 2.0 µF and the capacitor C2 has a capacitance of 4.0 uF. While the switch S is open, the potential difference across C, is 10 V and C2 is uncharged. After closing the switch, the total energy (in J) stored by the two capacitors is: C O 15 x 10-5 O 5.0 x 10-5 O 1.0 x 10-4 О 33x 10-5 3.0 x 10-4

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 52P: Consider the circuit shown in Figure P20.52, where C1 = 6.00 F, C2 = 3.00 F, and V = 20.0 V....
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For the circuit shown, the capacitor C, has a capacitance of 2.0 µF and the
capacitor C2 has a capacitance of 4.0 uF. While the switch S is open, the potential
difference across C, is 10 V and C2 is uncharged. After closing the switch, the total
energy (in J) stored by the two capacitors is:
C1
O 1.5 x 10-5
O 5.0 x 10-5
O 1.0 x 10-4
O 3.3 x 10-5
O3.0 x 10-4
Transcribed Image Text:For the circuit shown, the capacitor C, has a capacitance of 2.0 µF and the capacitor C2 has a capacitance of 4.0 uF. While the switch S is open, the potential difference across C, is 10 V and C2 is uncharged. After closing the switch, the total energy (in J) stored by the two capacitors is: C1 O 1.5 x 10-5 O 5.0 x 10-5 O 1.0 x 10-4 O 3.3 x 10-5 O3.0 x 10-4
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