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For the cross-tabulation data shown below, which represents a count of the type of books that individuals prefer, verify that the assumptions of the chi-square test are not met, and aggregate the data in an appropriate way so that the assumptions are met. Then conduct a chi-square test for independence at the 0.05 level of sign Gender Romance Fiction Male Female $ 5 Nonfiction 5 3 5 Autobiography 8 0 First, verify that the assumptions are not met. More than 20% of cells have expected frequencies smaller than 5. There are no expected frequencies of zero. Therefore, the assumptions are not met. Determine which sets of data to group together, and create the new, aggregated data table. Gender Male Fiction Nonfiction/Romance/Autobiography 12 10 Female (Type whole numbers.) Next, write the hypotheses for the chi-square test for independence H Gender and Book Preference are independent H, Gender and Book Preference are dependent Find the expected frequencies Gender Fiction Nonfiction/Romance! Autobiography Grand Total Male 7.43 12.57 20 Female 5.57 9.43 15 Grand Total 13 22 35 (Type integers or decimals rounded to two decimal places as needed.) Compute the chi-square statistic 0.10 (Type an integer or decimal rounded to two decimal places as needed.) Find the p-value and draw a conclusion. p-value- (Type an integer or decimal rounded to three decimal places as needed.).

For the cross-tabulation data shown below, which represents a count of the type of books that individuals prefer, verify that the assumptions of the chi-square test are not met, and aggregate the data in an appropriate way so that the assumptions are met. Then conduct a chi-square test for independence at the 0.05 level of sign Gender Romance Fiction Male Female $ 5 Nonfiction 5 3 5 Autobiography 8 0 First, verify that the assumptions are not met. More than 20% of cells have expected frequencies smaller than 5. There are no expected frequencies of zero. Therefore, the assumptions are not met. Determine which sets of data to group together, and create the new, aggregated data table. Gender Male Fiction Nonfiction/Romance/Autobiography 12 10 Female (Type whole numbers.) Next, write the hypotheses for the chi-square test for independence H Gender and Book Preference are independent H, Gender and Book Preference are dependent Find the expected frequencies Gender Fiction Nonfiction/Romance! Autobiography Grand Total Male 7.43 12.57 20 Female 5.57 9.43 15 Grand Total 13 22 35 (Type integers or decimals rounded to two decimal places as needed.) Compute the chi-square statistic 0.10 (Type an integer or decimal rounded to two decimal places as needed.) Find the p-value and draw a conclusion. p-value- (Type an integer or decimal rounded to three decimal places as needed.).

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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For the cross-tabulation data shown below, which represents a count of the type of books that individuals prefer, verify that the assumptions of the chi-square test are not met, and aggregate the data in an appropriate way so that the assumptions are met. Then conduct a chi-square test for independence at the 0.05 level of significance. Autobiography Gender Male Female Fiction S5 Nonfiction Romance 1 5 8 0 3 5 First, vently that the assumptions are not met More than 20% of cells have expected frequencies smaller than 5. There are no expected frequencies of zero. Therefore, the assumptions are not met. Determine which sets of data to group together, and create the new, aggregated data table Gender Fiction Male Female 8 5 Nonfiction/Romance/Autobiography 12 10 (Type whole numbers.) Next, write the hypotheses for the chi-square test for independence. Ho Gender and Book Preference are independent H₁: Gender and Book Preference are dependent Find the expected frequencies. Gender Fiction Nonfiction/Romance/ Autobiography Grand Total Male 7.43 12,57 20 Female Grand Total 5.57 13 9.43 22 15 35 (Type integers or decimals rounded to two decimal places as needed.) Compute the chi-square statistic. 0.18 Type an integer or decimal rounded to two decimal places as needed.) Find the p-value and draw a conclusion. p-value = (Type an integer or decimal rounded to three decimal places as needed.)
Transcribed Image Text:For the cross-tabulation data shown below, which represents a count of the type of books that individuals prefer, verify that the assumptions of the chi-square test are not met, and aggregate the data in an appropriate way so that the assumptions are met. Then conduct a chi-square test for independence at the 0.05 level of significance. Autobiography Gender Male Female Fiction S5 Nonfiction Romance 1 5 8 0 3 5 First, vently that the assumptions are not met More than 20% of cells have expected frequencies smaller than 5. There are no expected frequencies of zero. Therefore, the assumptions are not met. Determine which sets of data to group together, and create the new, aggregated data table Gender Fiction Male Female 8 5 Nonfiction/Romance/Autobiography 12 10 (Type whole numbers.) Next, write the hypotheses for the chi-square test for independence. Ho Gender and Book Preference are independent H₁: Gender and Book Preference are dependent Find the expected frequencies. Gender Fiction Nonfiction/Romance/ Autobiography Grand Total Male 7.43 12,57 20 Female Grand Total 5.57 13 9.43 22 15 35 (Type integers or decimals rounded to two decimal places as needed.) Compute the chi-square statistic. 0.18 Type an integer or decimal rounded to two decimal places as needed.) Find the p-value and draw a conclusion. p-value = (Type an integer or decimal rounded to three decimal places as needed.)
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