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- WATCH THIS TWO MINUTE VIDEO TO SOLVE https://www.youtube.com/watch?v=9Wxxv7kwXlA&list=PLE-217H0ao60Uzpzj-FNP_0ScVp5SZB7j&index=8 What is the theoretical yield of this experiment? 1.217g 49% 4.9g .0893gShow all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdkUse this video to answer the questions: https://www.youtube.com/watch?v=BocfSXdbaU0
- can you answer, please? the experimental data are Reference: https://www.youtube.com/watch?v=OOXRkycKEOc&feature=youtu.be and https://www.youtube.com/watch?v=3wLJLm0QLpg&feature=youtu.beIn Part B, you used a similar procedure to that of Part A to determine the mass percent of CaCO3 in an antacid tablet. The commercially accepted range of CaCO3 in an antacid tablet is 25–35% by mass. Miranda obtained the data below from her Part B trial: TRIAL PRESSURE (torr) MASS OF TABLET (g) TEMPERATURE (°C) VOLUME CO2 RECOVERED (mL) 1 750.5 0.5702 21.3 69.6 2 750.5 0.5622 21.2 68.2 Miranda determined her average % Recovery of CO2 to be 65.0% from Part A. Based on her data collected from Part A, was the average percent mass of CaCO3 in her antacid tablet within the commercially accepted range? Yes, her mass percent does fall within the commercially accepted range. No, her mass percent does not fall within the commercially accepted range.FOLLOW UP QUESTION: Answer #4 onlyQuality Assurance and Calibration Methods Link to previous answers:https://www.bartleby.com/questions-and-answers/a-0.2422-g-sample-of-a-certain-fruit-was-analyzed-for-the-content-of-a-certain-pesticide.-after-a-se/73201da3-a435-470d-af44-bbdc3d361b00
- A pilot plant reactor was charged with 50 kg naphthalene and 200 kg (98% by wt) H2SO4. The reaction goes to 90% completion. The product distribution was found to be 18.6% monosulfonate naphthalene and 81.4% disulphonate naphthalene. Calculate the complete analysis of the product.The atomic hydrogen exists in space at an estimated concentration of one particle per cubic meter. If the collision diameter is 2.5 ×10^(–10) meter and the temperature is 2.7 Kelvin, how many kilometers away will the next potential collision be? Express the answer in three significant figures.Here's the link https://www.youtube.com/watch?v=wY3ey4E-FRA
- A clinic had 25 patients on Friday morning. If 21 patientswere given flu shots, what percentage of the patientsreceived flu shots? Express your answer to the ones place.Given the Ksp for Ag2CrO4 is equal to 1.20 x 10-12, calculate the percent error in your experimentally determined value for average Ksp (this will be an extremely large percentage – think about why).Please see the activity sheet below for the context and question. Thank you