Q12. Which of the following is insoluble in water? A. HgCl2 C. Pbl; B. NaHCO, Q13. What volume (mL) of 1.00 M K,Cr,0, is required to completely react with 350. K2Cr,O7(ac) +6FESO.a + 7H,SOiagi > Cr;(SO.)tac) + 3Fe,(SO)alag + K;SC A. 58.4 B. 29.2 C. 292 Q14. Which equation represents the second ionization energy of Ca? A. Ca(g) → Ca"(g) + 1e B. Ca"(g) → Ca"(g) + le C. Ca(g) → Ca" (g) + 2e D. Ca (g) → Ca"(s) + 1e
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- A mixture containing only KCl and NaBr is analyzed by the Mohr Method. A 0.3172-g sample is dissolved in 50 mL water and titrated to the Ag2CrO4 endpoint, requiring 36.85 mL of 0.1120 M AgNO3. A blank titration requires 0.71 mL of titrant to reach the same endpoint. Report the % (w/w) KCl and NaBr in the sample. [Answer should be 82.41 % (w /w)]A mixture containing only KCl and NaBr is analyzed by the Mohr method. A 0.5072-g sample is dissolved in 50 mL of water and titrated to the Ag2CrO4 end point, requiring 36.85 mL of 0.1120 M AgNO3. A blank titration requires 0.71 mL of titrant to reach the same end point. Report the %w/w KCl and NaBr in the sample.KCl = 74.551 NaBr = 102.89A mixture containing only KCl and NaBr is analyzed by the Mohr method. A 0.3172-g sample is dissolved in 50 mL of water and titrated to the Ag,CrO4 end point, requiring 36.85 mL of 0.1120 M AgNO3. A blank titration requires 0.71 mL of titrant to reach the same end point. Report the %w/w KCl and NaBr in the sample.
- The mass of K3PO4 needed to prepare 250.0mL of an aqueous solution in which PO4-3 concentration is 0.0550M. The answer is ……………………… How many grams of silver sample is equal to 0.0417 mole of silver The answer is ……………………… When 38.0 mL of 0.1250 M H2SO4 is added to 100 mL of a solution of PbI2, a precipitate of PbSO4 forms. The PbSO4 is then filtered from the solution, dried, and weighed. If the recovered PbSO4 is found to have a mass of 0.0471g, what was the concentration of iodide ions in the original solution The answer is ……………………………… Express 96.342 m using 2 significant figures The answer is ………………………………. The oxidation number of sulfur in (Na2S2O5) is? The answer is ………………………………A mixture containing only KCl and NaBr is analyzed by the Mohr method. A 0.2125- g sample is dissolved in 25 mL of water and titrated to the Ag2CrO4 end point, requiring 25.63 mL of 0.1110 M AgNO3. A blank titration requires 1.15 mL of titrant to reach the same end point. Report the %w/w KCl and NaBr in the sample.KCl = 74.551 NaBr = 102.89What weight of sample in gram containing 8.00 % Fe3O4 (MW= 231.53 g/mole) must be taken to obtain a precipitate of Fe (OH)3 (MW= 106.867 g/mol) that, when ignited to Fe2O3 (MW = 159.69 g/mole), weighs 150.0 mg
- Ascorbic acid (Vitamin C, MW = 176.126g/mol) is a reducing agent, reacting as follows: C6H8O6 → C6H6O6 + 2H+ + 2e It can be determined by oxidation with a standard solution of I2. A 200.0-mL sample of a citrus fruit drink is acidified, and 10.00mL of 0.0500 M I2 is added. After the reaction is complete the excess I2 is titrated with 38.62 mL of 0.0120 M Na2S2O3 . Calculate the number of milligrams of ascorbic acid per milliliter of fruit drink. I2 +2e → 2I- I2 + 2Na2S2O3 → 2NaI + Na2S4O6A solution of I3- was standardized by titrating freshly dissolved arsenious oxide (As4O6, FM 395.683). The titration of 25.00 mL of a solution prepared by dissolving 0.3663 g of As4O6 in a volume of 100.0 mL required 31.77 mL of I3-. Calculate the molarity of the I3- solution. As4O6(s) + 6H2O ⇌ 4H3AsO3 H3AsO3 + I3- + H2O ⇌ H3AsO4 + 3I- + 2H+ a. 0.01657 M b. 0.02914 M c. 0.1166 M d. 0.0957 MHow many grams of CaF2 (molar mass 78.077) will dissolve in 250 mL of 0.20 M NaF solution? The Ksp for CaF2 is 3.8904e-11.
- A mixture containing only KCl and NaBr is analyzed by the Mohr method. A 0.2125-g sample is dissolved in 25 mL of water and titrated to the Ag2CrO4 endpoint, requiring 25.63 mL of 0.1110 M AgNO3. A blank titration requires 1.15 mL of titrant to reach the same end point. Report the %w/w KCl and NaBr in the sample. KCl = 74.551 NaBr = 102.89if 361.3 mg of Li2(SO4) (FW=109.95) is added to 450 mL of 0.828 M NH4F, what is the Qip for lithium fluoride. (Ksp of lithium fluoride= 3.8 x10^-3)3 L contaminated air 50 mL 0.0116 M in an air pollution analysisCarbon dioxide (CO2) BaCO3 is passed through Ba (OH) 2 solution.is precipitated as. Excess of base, next to phenol phthalate (f.f.) indicatorIt is titrated with 23.6 mL of 0.0108 M HCl. CO2 in this air sampleCalculate its concentration in ppm. (Density of CO2Take it as 1.98 g / L. C = 12, O = 16 g / mol).