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For the following question, you will not be able to find a general solution as there is no closed form formula to integrate e". So you should try to answer the question without integrating anything. dy = f'(t) is the slope of the tangent to the graph of y = f(t). Using this idea, explain why dt Observe that the functions with the given graphs can't be solutions of the differential equation dy = e* (y – 1)? dt

For the following question, you will not be able to find a general solution as there is no closed form formula to integrate e". So you should try to answer the question without integrating anything. dy = f'(t) is the slope of the tangent to the graph of y = f(t). Using this idea, explain why dt Observe that the functions with the given graphs can't be solutions of the differential equation dy = e* (y – 1)? dt

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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For the following question, you will not be able to find a general solution as there is no closed form formula to integrate e". So you should try to answer the question without integrating anything. dy = f'(t) is the slope of the tangent to the graph of y = f (t). Using this idea, explain why dt Observe that the functions with the given graphs can't be solutions of the differential equation dy dt (а) ул (b) У4 1 1 d?y [HINT: For part (b), first find - using implicit differentiation. Then what can you say about the sign of dt2 d²y dt2 (i.e. the concavity of the graph) for y > 1?]
Transcribed Image Text:For the following question, you will not be able to find a general solution as there is no closed form formula to integrate e". So you should try to answer the question without integrating anything. dy = f'(t) is the slope of the tangent to the graph of y = f (t). Using this idea, explain why dt Observe that the functions with the given graphs can't be solutions of the differential equation dy dt (а) ул (b) У4 1 1 d?y [HINT: For part (b), first find - using implicit differentiation. Then what can you say about the sign of dt2 d²y dt2 (i.e. the concavity of the graph) for y > 1?]
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