For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population The word counts of five essays are 504, 621, 546, 601, and 584. Use a sample size of 2. O The mean of the population is (Round to two decimal places as needed) The standard deviation of the population is (Round to two decimal places as needed.) Identify all samples of size 2 with the correct accompanying means below. DA. 504, 584, x= 544 O B. 546, 601, x= 5735 O C. 584, 504, x= 544 OD. 584, 546, x= 565 D E. 601, 546, x= 5735 O F. 584, 584, x = 584 OG. 584, 621, x= 6025 O H. 584, 628, x= 606 O1. 504, 546, x= 525 546, 584, x=565 OK. 504, 504, x= 504 J. OL 621, 601, x=611 OM. 621, 546, x= 583.5 ON. 621, 504, x= 5625 Oo. 546, 546, x= 546 P. 504, 601, x= 552 5 Oa 601, 601, x= 601 OR. 601, 504, x 552 5 OS. 621, 621, x= 621 OT 504, 621, x= 5625 O U. 601, 621 , x= 543 Ov. 601, 621, x=611 OW. 601, 584, x= 592.5 OX. 584, 601, x= 592.5 OY. 621, 584, x= 602.5 OZ. 546, 621, x= 583.5 O. 546, 504, x= 525 The mean of the sampling distribution is (Round to two decimal places as noeded) Next
For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population The word counts of five essays are 504, 621, 546, 601, and 584. Use a sample size of 2. O The mean of the population is (Round to two decimal places as needed) The standard deviation of the population is (Round to two decimal places as needed.) Identify all samples of size 2 with the correct accompanying means below. DA. 504, 584, x= 544 O B. 546, 601, x= 5735 O C. 584, 504, x= 544 OD. 584, 546, x= 565 D E. 601, 546, x= 5735 O F. 584, 584, x = 584 OG. 584, 621, x= 6025 O H. 584, 628, x= 606 O1. 504, 546, x= 525 546, 584, x=565 OK. 504, 504, x= 504 J. OL 621, 601, x=611 OM. 621, 546, x= 583.5 ON. 621, 504, x= 5625 Oo. 546, 546, x= 546 P. 504, 601, x= 552 5 Oa 601, 601, x= 601 OR. 601, 504, x 552 5 OS. 621, 621, x= 621 OT 504, 621, x= 5625 O U. 601, 621 , x= 543 Ov. 601, 621, x=611 OW. 601, 584, x= 592.5 OX. 584, 601, x= 592.5 OY. 621, 584, x= 602.5 OZ. 546, 621, x= 583.5 O. 546, 504, x= 525 The mean of the sampling distribution is (Round to two decimal places as noeded) Next
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Transcribed Image Text:For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and
them with the mean and standard deviation of the population.
The word counts of five essays are 504, 621, 546, 601, and 584. Use a sample size of 2. O
compare
The mean of the population is
(Round to two decimal places as needed.)
The standard deviation of the population is
(Round to two decimal places as needed.)
Identify all samples of size 2 with the correct accompanying means below.
A. 504, 584, x= 544
B. 546, 601, x= 573.5
C. 584, 504, x 544
D. 584, 546, x= 565
E. 601, 546, x= 573.5
F. 584, 584, x- 584
G. 584, 621, x= 602.5
H. 584, 628, x= 606
I. 504, 546, x- 525
J. 546, 584, x= 565
K. 504, 504, x= 504
L. 621, 601, x3611
M. 621, 546, x = 583.5
O N. 621, 504, x= 562.5
O 0. 546, 546, x= 546
P. 504, 601, x= 552.5
Q. 601, 601, x= 601
O R. 601, 504, x = 552.5
S. 621, 621, x= 621
T. 504, 621, x= 562.5
U. 601, 621, x = 543
V. 601, 621, x =611
| W. 601, 584, x= 592.5
O X. 584, 601, x= 592.5
O Y. 621, 584, x= 602.5
O Z. 546, 621, x= 583.5
O: 546, 504, x = 525
The mean of the sampling distribution is
(Round to two decimal places as needed.)
Next
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