For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard devi sampling distribution and compare them with the mean and standard deviation of the population. The scores of three students in a study group on a test are 93, 95, 92. Use a sample size of 3.O The mean of the population is . (Round to two decimal places as needed.) The standard deviation of the population is (Round to two decimal places as needed.) Identify all samples of size 3 with the correct accompanying means below. DA. 92,95,92 x = 93 O B. 95,95,92 x = 94 O c. 93.95.92 x= 93.33 OF. 92,92,93 x = 92.33 O1. 92,93,92 x = 92.33 OL. 93,92,95 x = 93.33 O D. 95,92,93 x= 93.33 O E. 93,95,93 x= 93.67 O G. 92,92,92 x = 92 H. 95,93,93 x = 93.67 O J. 92.95,93 x = 93.33 O K. 95.92.92 x= 93 O M. 92,93,95 x = 93.33 N. 93,93,93 x= 93 O o. 95,93.92 x= 93.33 O P. 95,95,95 x = 95 O Q. 95,92,95 x = 94 R. 93,95,95 x = 94.33 O s. 95,95,93 x= 94.33 O T. 92,95,95 x = 94 O U. 92,92,95 x= 93 O V. 93,93,92 x= 92.67 O W. 93,92,92 x= 92.33 O X. 92,93,93 x = 92.67 O Y. 93,93,95 x = 93.67 O Z. 95,93,95 x= 94.33 O. 93,92,93 x= 92.67 %3D %3D The mean of the sampling distribution is (Round to two decimal places as needed.) The standard deviation of the sampling distribution is (Round to two decimal places as needed.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Author:Carter
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Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the
sampling distribution and compare them with the mean and standard deviation of the population.
The scores of three students in a study group on a test are 93, 95, 92. Use a sample size of 3. D
The mean of the population is.
(Round to two decimal places as needed.)
The standard deviation of the population is.
(Round to two decimal places as needed.)
Identify all samples of size 3 with the correct accompanying means below.
A. 92,95,92 x = 93
B. 95,95,92 x = 94
C. 93,95,92 x = 93.33
D. 95,92,93 x = 93.33
E. 93,95,93 x= 93.67
F. 92,92,93 x= 92.33
O G. 92,92,92 x = 92
H. 95,93,93 x = 93.67
I.
92,93,92 x = 92.33
O J. 92,95,93 x = 93.33
K. 95,92,92 x = 93
L. 93,92,95 x= 93.33
M. 92,93,95 x = 93.33
N. 93,93,93 x = 93
O. 95,93,92 x= 93.33
P.
95,95,95 x = 95
Q. 95,92,95 x = 94
R. 93,95,95 x= 94.33
S. 95,95,93 x = 94.33
T. 92,95,95 x = 94
U. 92,92.95 x= 93
V. 93,93,92 x = 92.67
O v.
W. 93,92,92 x= 92.33
X. 92,93,93 x = 92.67
O Y. 93,93,95 x = 93.67
Z. 95,93,95 x = 94.33
O: 93,92,93 x = 92.67
The mean of the sampling distribution is.
(Round to two decimal places as needed.)
The standard deviation of the sampling distribution is
(Round to two decimal places as needed.)
Click to select your answer(s).
?
11:44 AM
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Transcribed Image Text:For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population. The scores of three students in a study group on a test are 93, 95, 92. Use a sample size of 3. D The mean of the population is. (Round to two decimal places as needed.) The standard deviation of the population is. (Round to two decimal places as needed.) Identify all samples of size 3 with the correct accompanying means below. A. 92,95,92 x = 93 B. 95,95,92 x = 94 C. 93,95,92 x = 93.33 D. 95,92,93 x = 93.33 E. 93,95,93 x= 93.67 F. 92,92,93 x= 92.33 O G. 92,92,92 x = 92 H. 95,93,93 x = 93.67 I. 92,93,92 x = 92.33 O J. 92,95,93 x = 93.33 K. 95,92,92 x = 93 L. 93,92,95 x= 93.33 M. 92,93,95 x = 93.33 N. 93,93,93 x = 93 O. 95,93,92 x= 93.33 P. 95,95,95 x = 95 Q. 95,92,95 x = 94 R. 93,95,95 x= 94.33 S. 95,95,93 x = 94.33 T. 92,95,95 x = 94 U. 92,92.95 x= 93 V. 93,93,92 x = 92.67 O v. W. 93,92,92 x= 92.33 X. 92,93,93 x = 92.67 O Y. 93,93,95 x = 93.67 Z. 95,93,95 x = 94.33 O: 93,92,93 x = 92.67 The mean of the sampling distribution is. (Round to two decimal places as needed.) The standard deviation of the sampling distribution is (Round to two decimal places as needed.) Click to select your answer(s). ? 11:44 AM e Type here to search の 2/1/2021 DII PrtScn F8 End F10 Pgup Home F1 PgDn F12 F3 F4 F5 F6 F7 63 & 6. 7 9- E R T Y U
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