For the formation of 5.95 mol of water, how many moles of nitric acid are needed? Zn + HNO3 → Zn(NO3)2 + NH4NO3 + H2O Molar Mass: Zn: 65.39 g/mol O: 16 g/mol H: 1.01 g/mol N: 14.01 g/mol Round off your answer to 2 decimal places.
For the formation of 5.95 mol of water, how many moles of nitric acid are needed? Zn + HNO3 → Zn(NO3)2 + NH4NO3 + H2O Molar Mass: Zn: 65.39 g/mol O: 16 g/mol H: 1.01 g/mol N: 14.01 g/mol Round off your answer to 2 decimal places.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter19: The Chemistry Of The Main-group Elements
Section: Chapter Questions
Problem 65QRT
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For the formation of 5.95 mol of water, how many moles of nitric acid are needed?
Zn + HNO3 → Zn(NO3)2 + NH4NO3 + H2O
Molar Mass:
Zn: 65.39 g/mol
O: 16 g/mol
H: 1.01 g/mol
N: 14.01 g/mol
Round off your answer to 2 decimal places.
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