The manufacture of aluminum includes the production of cryolite (Na3AlF6) from the following reaction: 6〖HF〗_((g))+3〖NaAlO〗_(2(s))→ 〖Na〗_3 〖AlF〗_(6(s))+3H_2 O_((l))+ 〖Al〗_2 O_(3(s)) How much HF (hydrogen sulfide) is required to produce 2.50kg of Na3AlF6?
The manufacture of aluminum includes the production of cryolite (Na3AlF6) from the following reaction: 6〖HF〗_((g))+3〖NaAlO〗_(2(s))→ 〖Na〗_3 〖AlF〗_(6(s))+3H_2 O_((l))+ 〖Al〗_2 O_(3(s)) How much HF (hydrogen sulfide) is required to produce 2.50kg of Na3AlF6?
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.87PAE
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The manufacture of aluminum includes the production of cryolite (Na3AlF6) from the following reaction:
6〖HF〗_((g))+3〖NaAlO〗_(2(s))→ 〖Na〗_3 〖AlF〗_(6(s))+3H_2 O_((l))+ 〖Al〗_2 O_(3(s))
- How much HF (hydrogen sulfide) is required to produce 2.50kg of Na3AlF6?
- How many cm3 of HF(g) are needed to produce 26.0g of Na3AlF6? The density of HF (g) at 25is 1.15g/L.
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