Question

Asked Apr 26, 2019

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For the function f(x) = 6- 4x^2 on the interval [-1,8] the mean slope of this function is -252/9.

By the mean value theorem, there exists a c in the open interval (-1,8) such that f '(c) is eqaul to the mean slope. What is the value of c and how do you find it?

Step 1

**Calculation:**

The given function is *f(x) = 6 – 4x ^{2} *and the given interval is [

It is given that the mean slope of the function on the interval is *– 252/9*.

Calculate the derivative of the function *f(x)* as follows.

Step 2

By mean value theorem the function *f′(x) *is equal to the mean slo...

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