For the given confidence level and values of x and n, find the following.x = 46, n= 98, confidence level 90%Part: 0/ 3Part 1 of 3(a) Find the point estimate. Round the answers to at least four decimal places, if necessary.The point estimate for the given data isSkip PartCheck AnswerSave For LateO2022 McGraw Hill LLC. All Rights Reservee here to searchW

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Answered: For the given confidence level and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The state education commission wants to estimate the fraction of tenth-grade students that have reading skills at or below the eighth-grade level. Step 2 of 2 : Suppose a sample of 1134 tenth graders is drawn. Of the students sampled, 226 read at or below the eighth-grade level. Using the data, construct the 99% confidence interval for the population proportion of tenth graders reading at or below the eighth-grade level. Round your answers to three decimal places.
We wish to estimate what percent of adult residents in a certain county are parents. Out of 100 adult residents sampled, 95 had kids. Based on this, construct a 90% confidence interval for the proportion p of adult residents who are parents in this county.Express your answer in tri-inequality form. Give your answers as decimals, to three places. < p < Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.p = ______± ______ Submit QuestionQuestion 5
The bank's manager would like to estimate the true proportion p of calls to the bank's customer service center that are answered in less than 30 seconds. (a) What conditions must be met to calculate a 95% confidence interval for p? show that the conditions are met in this case. (b) A 95% confidence interval for p is (0.783, 0.877). GIve the margin of error and show how it was calculated. (c) Interpret the interval from part (c) in context. Construct and interpret a 95% confidence interval for the true mean response time of calls to the bank's customer service center. Is the customer service center meeting its goal of answering calls in less than 30 seconds? Give appropriate evidence to support your answer. If the service center is meeting its goals, what do you think is being done to ensure this happens? If the service center is not meeting their goals, what can be changed or implemented to make sure they do?
Jane wants to estimate the proportion of 13 students on her campus 4 who eat cauliflower. After surveying students, she finds who eat cauliflower. Obtain and interpret a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method.
Determine the t values that correspond to the boundaries for the confidence level desired. If the desired confidence level is 80%, for a sample of n=31 individuals, what t values form the boundaries for the middle 80% and the most extreme 20%?
The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of people who appear on the list that are actually caught. Step 2 of 2 : Suppose a sample of 772 suspected criminals is drawn. Of these people, 510 were not captured. Using the data, construct the 98% confidence interval for the population proportion of people who are captured after appearing on the 10 Most Wanted list. Round your answers to three decimal places.
The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of people who appear on the list that are actually caught. Step 2 of 2: Suppose a sample of 871 suspected criminals is drawn. Of these people, 243 were captured. Using the data, construct the 99%confidence interval for the population proportion of people who are captured after appearing on the 10 Most Wanted list. Round your answers to three decimal places.
The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of people who appear on the list that are actually caught. Step 2 of 2: Suppose a sample of 531 suspected criminals is drawn. Of these people, 201 were captured. Using the data, construct the 95% confidence interval for the population proportion of people who were caught after being on the 10 Most Wanted list. What are the LOWER endpoints and UPPER endpoints round your answers to three decimal points
The mean number of hours watching TV per week for a sample of 153 teenagers is 27. If the margin of error for the population mean with a 98%98% confidence interval is 1.2, construct a 98% confidence interval for the mean number of hours watching TV per week for all teenagers.
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. Step 2 of 2 : Suppose a sample of 310310 tenth graders is drawn. Of the students sampled, 4646 read at or below the eighth grade level. Using the data, construct the 85%85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level. Round your answers to three decimal places.
A poll surveyed 1024 people about global warming. Of those surveyed, 389 said that they thought global warming would pose a serious threat to their way of life in their lifetime. a) Define p and for this problem. Which is the one that we will estimate a confidence interval? Which is the one that we know from the survey and what is it? b) Find a 90% confidence interval for the population proportion of people that think global warming will pose a serious threat to their way of life in their lifetime. c) From this survey, can we be 90% confident that the majority of people do not think global warming will pose a serious threat to their way of life in their lifetime? Why?
The maker of a cell phone screen protector would like to estimate the proportion of customers who file a warranty claim. To do so, they select a random sample of 200 customers and determine that the 96% confidence interval for the true proportion of customers who file a warranty claim to be 0.15 to 0.28. Which of the following would decrease the margin of error? selecting another sample decreasing the sample size increasing the confidence level decreasing the confidence level

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