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- Equation: Vt= Vm sin 120π t Solve Vrms and VaverageThe voltage and current at the terminals of an ideal basic circuit element are zero for t < 0. For t > or = 0, they are: v = 100e^-50t(sin150t) V i = 20e^-50t(sin150t) A a) Find the power absorbed by the element at t = 20 ms. b) Find the total energy absorbed by the circuit.1. For the following sinusoids, determine which one leads and by how much a. ?(?) = 10cos (4? − 60°) and ?(?) = 6sin (4? + 50°)b. ?ଵ(?) = 4cos (377? + 10°) and ?ଶ(?) = −20cos(377?)c. ?(?) = 13 cos(2?) + 5 sin(2?) and ?(?) = 15cos (2? − 11.8°)
- A circuit is designed with an AC source of max voltage 12 and frequency 60 Hz. The circuit has a resistance of 1050 Ohms, an inductance of 0.06 Henrys, and a capacitance of 0.009 coulombs per volt. - omega for source in rad/s? - omegaR for circuit? -XL? -XC? -phi in radians? -Z? -imax?Ac - 100 VrmsR1 - 1kR2 - 500Rload - 1kCapacitor - 2uF Q1. How much is the capacitor voltage lagging from the AC sourceShow that at a given frequency ω, the circuits will have the same impedance between the terminals a,b ifR1=R21+ω2R22C22,C1=1+ω2R22C22ω2R22C2.2. Find the values of resistance and capacitance that when connectedin series will have the same impedance at 40 krad/s as that of a1000 Ω resistor connected in parallel with a 50 nF capacitor.
- Given: L1 = 17 mHL2 = 21 mHL3 = 0.014 HL4 = 11981 mHL5 = 89 uH Calculate the total inductance of the circuit, LT.1. What is the shortest time required for a 4.3-krad/s sinusoid to increase from two-fifths to four-fifths of its peak value ? CHOICES: A. 120 s B. 140 s C. 160 s D. 180 s E. NOTA 3. A voltage across a 0.5 H is provided below. What is sinusoidal expression for the current? e =100 sin 20 t4. The voltage across 1 micro farrad capacitor is provided below. What is the sinusoidal expression for the current? e= 30 sin 400 t
- 1) Given the sinusoids v1(t) = 8cos (250t +15°) V and v2(t) = 6cos (250t – 45°) V, determine the time by which v2(t) is advanced or delayed with respect to v1(t).An AC circuit contains a 24-Ω resistor, a 15.9-mH inductor, and a 13.3-µF capacitor connected in parallel. The circuit is connected to a 240-V, 400-Hz power supply. Find the following values. P = I2 / R = VARsL = √VA squared - P squared = VARsC = VARsL(present) - VARsL(needed) =Get the sum of two signals.V1 = a sin (120?t + b)V2 = c sin (120?t + d)Given:a = 22b = 15°c = 13d = 32°