For the part circled, why do I keep getting 4860 nm? I cannot figure out the calculation for nm to m and vise versa

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter5: Electron Configurations And The Periodic Table
Section: Chapter Questions
Problem 136QRT: According to a relationship developed by Niels Bohr, for an atom or ion that has a single electron,...
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For the part circled, why do I keep getting 4860 nm? I cannot figure out the calculation for nm to m and vise versa

Class Example: Using the Bohr Model
Calculate the Wavelength of Light Emitted when an
electron in the H atom falls from the n = 4 to n = 2 level
[12
AE = -2.178 × 10-18]
22
121
= -4.084 x 10-191
%3D
%3D
42
hc
hc
AE = Ephoton= hv = →
%3D
%3D
JAE|
(6.626 × 10-34y s)(2.998 × 108 m/s) 1× 10° nm
23=
= 486 nm
%3D
|- 4.084 × 10-19/|
1m
Energy emitted falls in the visible light region
4.86mx/0-7
2014 Pearson Education, Inc.
Transcribed Image Text:Class Example: Using the Bohr Model Calculate the Wavelength of Light Emitted when an electron in the H atom falls from the n = 4 to n = 2 level [12 AE = -2.178 × 10-18] 22 121 = -4.084 x 10-191 %3D %3D 42 hc hc AE = Ephoton= hv = → %3D %3D JAE| (6.626 × 10-34y s)(2.998 × 108 m/s) 1× 10° nm 23= = 486 nm %3D |- 4.084 × 10-19/| 1m Energy emitted falls in the visible light region 4.86mx/0-7 2014 Pearson Education, Inc.
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