For the reaction; 4H+   +  PbO2  + 2 Fe 2+ →  2 Fe 3+ + Pb2+  +  2 H2O, the standard electrode potential is 0.69 V. Calculate the Gibbs Free-Energy that occur in the system if the product quotient of the reaction is 0.001.

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter18: Introduction To Electrochemistry
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Problem 18.4QAP
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For the reaction; 4H+   +  PbO2  + 2 Fe 2+ →  2 Fe 3+ + Pb2+  +  2 H2O, the standard electrode potential is 0.69 V. Calculate the Gibbs Free-Energy that occur in the system if the product quotient of the reaction is 0.001.

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