For the reaction N₂O4 (9) 2NO₂ (g), the value of K at 25°C is 7.19 x 10-3 ▼ Part A Calculate [N₂04] at equilibrium when [NO₂] =2.40 × 10-2mol/L 15| ΑΣΦ [N₂04] = Submit Part B Request Answer → ? Calculate [NO₂] at equilibrium when [N₂O4]-7.80 x 10-2mol/L. 195| ΑΣΦ ? mol/L

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<Ch 7 Homework
Problem 7.55
1
For the reaction N₂O4 (9) 2NO2 (g), the value of K at 25°C is
7.19 x 10-3
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O
II
Part A
Calculate [N₂04] at equilibrium when [NO₂] =2.40 × 10-2mol/L.
[N₂O4] =
Submit
Part B
[NO₂] =
ΫΠΙ ΑΣΦ
Submit
Request Answer
Calculate [NO₂] at equilibrium when [N₂O4] = 7.80 x 10-2mol/L.
VGI ΑΣΦ
Request Answer
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?
?
mol/L
mol/L
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Transcribed Image Text:<Ch 7 Homework Problem 7.55 1 For the reaction N₂O4 (9) 2NO2 (g), the value of K at 25°C is 7.19 x 10-3 Type here to search O II Part A Calculate [N₂04] at equilibrium when [NO₂] =2.40 × 10-2mol/L. [N₂O4] = Submit Part B [NO₂] = ΫΠΙ ΑΣΦ Submit Request Answer Calculate [NO₂] at equilibrium when [N₂O4] = 7.80 x 10-2mol/L. VGI ΑΣΦ Request Answer Translate ? ? mol/L mol/L New
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