27 A * NO LTEI 27% Ô 10:27 PM25. find the magnetic energy stored in inductor when it reaches the steady state ( time = infinity ).a. 5.8 x 10-9 Jb. 5.8 x 103 Jc. 0.015 Jd. none of these26. If the switch is thrown from a to b suddenly, how long will it take for the current to drop to 0.02 A?a. 1.82 µsb. 2.73 µsc. 3.51 usd. 4.82 use. none of these27. What is the voltage across the inductor when the current drops down to 0.02 A? ( Hint: use VL =L(di/dt)by taking the derivative. )a. 2.00 Vb. 3.00 Vc. 4.00 Vd. 5.00 Ve. none of these28. Two inductors, L1 = 600 mH and L2 = 400 mH, are connected in parallel, what is the equivalentinductance?a. 100 mHb. 292 mHc. 200 mHd. 240 mH : NO TEI 27% Ô 10:27 PMFor the RL circuit as shown in the following: R = 150 Ohms, L= 0.38 mH and E = 12.00 V%3DaeeeeeR23. find the time constant.a. 2.53 msb. 2.53 µsc. 2.53 secd. none of these24. When the switch is thrown to point a, what is the current at t = 5.0 µs ?a. 28.7 mAb. 34.7 mAc. 68.9 mAd. 11.0 mA

Answered: For the RL circuit as shown in the…

For the RL circuit as shown in the following: R = 150 Ohms, L= 0.38 mH and E = 12.00 V a Leele R 23. find the time constant.

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter14: Inductance

Section: Chapter Questions

Problem 3CQ: The ignition circuit of an automobile is powered by a 12-V battery. How are we able generate large...

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Question

A * NO LTEI 27% Ô 10:27 PM
25. find the magnetic energy stored in inductor when it reaches the steady state ( time = infinity ).
a. 5.8 x 10-9 J
b. 5.8 x 103 J
c. 0.015 J
d. none of these
26. If the switch is thrown from a to b suddenly, how long will it take for the current to drop to 0.02 A?
a. 1.82 µs
b. 2.73 µs
c. 3.51 us
d. 4.82 us
e. none of these
27. What is the voltage across the inductor when the current drops down to 0.02 A? ( Hint: use VL =L(di/dt)
by taking the derivative. )
a. 2.00 V
b. 3.00 V
c. 4.00 V
d. 5.00 V
e. none of these
28. Two inductors, L1 = 600 mH and L2 = 400 mH, are connected in parallel, what is the equivalent
inductance?
a. 100 mH
b. 292 mH
c. 200 mH
d. 240 mH

: NO TEI 27% Ô 10:27 PM
For the RL circuit as shown in the following: R = 150 Ohms, L= 0.38 mH and E = 12.00 V
%3D
a
eeeee
R
23. find the time constant.
a. 2.53 ms
b. 2.53 µs
c. 2.53 sec
d. none of these
24. When the switch is thrown to point a, what is the current at t = 5.0 µs ?
a. 28.7 mA
b. 34.7 mA
c. 68.9 mA
d. 11.0 mA

Expert Solution

Step 1

$27) I_{m a x} = 12 / 150 = 0.08 A N o w, c u r r e n t = 0.02 A c h a n g e i n c u r r e n t = | 0.02 - 0.08 | = 0.06 A U \sin g r e l a t i o n I = I_{m a x} (1 - e^{- R t / L}) 0.02 = 0.08 (1 - e^{- 150 t / 0.00038}) 0.75 = e^{- 394736.8 t} - 0.28768 = - 394736.8 t t = 7.288 * 10^{- 7} s e c$

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