For the situation in the figure below, use momentum conservation to determine (a) the magnitude and (b) the direction of the final velocity of ball 1 after the collision. The angle = 42.0°. (a) Number i 101 = 0.900 m/s m₁ = 0.150 kg (b) Number i ¹02 = 0.540 m/s m₂ = 0.260 kg 6 Units Units +y ly +V (a) 241x 35.0 (b) (a) Top view of two balls colliding on a horizontal surface. (b) This part of the drawing shows the x and y components of the velocity of ball 1 after the collision. 241 +x 2= 0.700 m/s
For the situation in the figure below, use momentum conservation to determine (a) the magnitude and (b) the direction of the final velocity of ball 1 after the collision. The angle = 42.0°. (a) Number i 101 = 0.900 m/s m₁ = 0.150 kg (b) Number i ¹02 = 0.540 m/s m₂ = 0.260 kg 6 Units Units +y ly +V (a) 241x 35.0 (b) (a) Top view of two balls colliding on a horizontal surface. (b) This part of the drawing shows the x and y components of the velocity of ball 1 after the collision. 241 +x 2= 0.700 m/s
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter11: Collisions
Section: Chapter Questions
Problem 41PQ: Initially, ball 1 rests on an incline of height h, and ball 2 rests on an incline of height h/2 as...
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