For this question, imagine you are hanging a basket with the red cables shown below. Note that all the cables are the same length. Determine the tension (pulling force) in cables OA, OB, OC, and OD for the 4 cases described below. As the system is symmetric, the resulting force of the cables is directly up in the z direction and equal to the weight placed at the center the basket. For this calculation, you may neglect the weight of the basket itself. For this problem you will be calculating the tension in the cables for 4 different cases. There are two different weights that can be placed in the center of the basket (5 lb and 10 Ib) and two different values for the distance h (12 inches and 24 inches) Solve for the tension (magnitude of the force vector) in each cable for the described cases. Case 1:5 lb and h=12 inch Case 2: 10 Ib and h=12 inch Case 3:5 lb and h=24 inch Case 4: 10 Ib and h=24 inch HINT 1: Decompose the vectors into Cartesian Coordinates once using variables and then plug in numbers for the weight and h at the end. This will save on calculation time! HINT 2: -Foc= weight applied in the z direction = Foxt Fout Foc+ Foo (i.e. the resultant forces in cables OA, OB, OC, and OD is equal and opposite to the force in cable OE) HINT 3: Based on the symmetry in this scenario, the tension in each cable is the same. w= 15 inches I-15 inches w/2 1/2 h= case dependent h B D A w
For this question, imagine you are hanging a basket with the red cables shown below. Note that all the cables are the same length. Determine the tension (pulling force) in cables OA, OB, OC, and OD for the 4 cases described below. As the system is symmetric, the resulting force of the cables is directly up in the z direction and equal to the weight placed at the center the basket. For this calculation, you may neglect the weight of the basket itself. For this problem you will be calculating the tension in the cables for 4 different cases. There are two different weights that can be placed in the center of the basket (5 lb and 10 Ib) and two different values for the distance h (12 inches and 24 inches) Solve for the tension (magnitude of the force vector) in each cable for the described cases. Case 1:5 lb and h=12 inch Case 2: 10 Ib and h=12 inch Case 3:5 lb and h=24 inch Case 4: 10 Ib and h=24 inch HINT 1: Decompose the vectors into Cartesian Coordinates once using variables and then plug in numbers for the weight and h at the end. This will save on calculation time! HINT 2: -Foc= weight applied in the z direction = Foxt Fout Foc+ Foo (i.e. the resultant forces in cables OA, OB, OC, and OD is equal and opposite to the force in cable OE) HINT 3: Based on the symmetry in this scenario, the tension in each cable is the same. w= 15 inches I-15 inches w/2 1/2 h= case dependent h B D A w
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter4: Coplanar Equilibrium Analysis
Section: Chapter Questions
Problem 4.41P: The center of gravity of the 3000-lb car is at G. The car is parked on an incline with the parking...
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Transcribed Image Text:For this question, imagine you are hanging a basket with the red cables shown below. Note that all the
cables are the same length. Determine the tension (pulling force) in cables OA, OB, OC, and OD for the 4
cases described below. As the system is symmetric, the resulting force of the cables is directly up in the z
direction and equal to the weight placed at the center the basket. For this calculation, you may neglect
the weight of the basket itself.
For this problem you will be calculating the tension in the cables for 4 different cases. There are two
different weights that can be placed in the center of the basket (5 lb and 10 Ib) and two different values
for the distance h (12 inches and 24 inches)
Solve for the tension (magnitude of the force vector) in each cable for the described cases.
Case 1:5 lb and h=12 inch
Case 2: 10 lb and h=12 inch
Case 3: 5 lb and h=24 inch
Case 4: 10 Ib and h=24 inch
HINT 1: Decompose the vectors into Cartesian Coordinates once using variables and then plug in
numbers for the weight and h at the end. This will save on calculation time!
HINT 2: -FoL= weight applied in the z direction = Foa+ Fout Foct Foo (i.e. the resultant forces in cables OA,
OB, OC, and OD is equal and opposite to the force in cable OE)
HINT 3: Based on the symmetry in this scenario, the tension in each cable is the same.
w= 15 inches
l=15 inches
w/2,
1/2
h= case dependent
B
D
A
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