for this question. The equilibrium constant, K, for the following reaction is 1.20x 10-2 at 500 K. PCI5(9) PCl3(g) + Cl₂(9) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.242 M PCI5, 5.39x 10-2 M PCl3 and 5.39x10-2 M Cl₂. What will be the concentrations of the three gases once equilibrium has been eestablished, if 4.68x 10-2 mol of Cl₂(g) is added to the flask? [PCI5] M [PC|3] = M [Cl₂] = M Retry Entire Group 1 more group attempt remaining Previous Next Submit Answer

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Chapter12: Chemical Equilibrium
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Use the References to access important values if needed for this question.
The equilibrium constant, K, for the following reaction is 1.20x 10-2 at 500 K.
PCI5(9) PC|3(g) + Cl₂(9)
An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.242 M PCI5, 5.39x10-2 M
PCl3 and 5.39x 10-2 M Cl₂. What will be the concentrations of the three gases once equilibrium has been
reestablished, if 4.68x 10-2 mol of Cl₂(g) is added to the flask?
[PCIs] =
IM
[PC|3] =
M
[Cl₂] =
M
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Transcribed Image Text:cator=assignment-take Use the References to access important values if needed for this question. The equilibrium constant, K, for the following reaction is 1.20x 10-2 at 500 K. PCI5(9) PC|3(g) + Cl₂(9) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.242 M PCI5, 5.39x10-2 M PCl3 and 5.39x 10-2 M Cl₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 4.68x 10-2 mol of Cl₂(g) is added to the flask? [PCIs] = IM [PC|3] = M [Cl₂] = M Retry Entire Group 1 more group attempt remaining Previous Next> WEB 48 One Touch Web Access Without Booting Up NumLk Prt Sc Submit Answer SONY Other Bookmarks 4:22 AM 4/30/2022 VGN-NW350F Delete Break
Use the References to access important values if needed for this question.-
The equilibrium constant, K, for the following reaction is 1.80 x 10-4 at 298 K.
NH4HS(s) NH3(9) + H₂S(g)
An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 298 K contains 0.336 mol NH4HS,
1.34× 10-2 M NH3 and 1.34× 10-2 M H₂S. If the concentration of NH3(g) is suddenly increased to
2.36x 10-2 M, what will be the concentrations of the two gases once équilibrium has been reestablished?
M
[NH3] =
[H₂S] =
M
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Transcribed Image Text:Use the References to access important values if needed for this question.- The equilibrium constant, K, for the following reaction is 1.80 x 10-4 at 298 K. NH4HS(s) NH3(9) + H₂S(g) An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 298 K contains 0.336 mol NH4HS, 1.34× 10-2 M NH3 and 1.34× 10-2 M H₂S. If the concentration of NH3(g) is suddenly increased to 2.36x 10-2 M, what will be the concentrations of the two gases once équilibrium has been reestablished? M [NH3] = [H₂S] = M Retry Entire Group 1 more group attempt remaining Previous Next> DISPLAY WEB One Touch Web Access Without Booting Up Prt Sc Insert F11 F12 Numn Lk Scr Lk Sys Ra Submit Answer F8 SONY F10 B Other Bookmarks ? 40 4:22 AM 4/30/2022 VGN-NW35OF Pause Delete Break
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