from 0.8778 g/mL, please calculate the mass (in ug) of 71.38 nL of liquid 1.

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Q1. from 0.8778 g/mL, please calculate the mass (in ug) of 71.38 nL of liquid 1.

 

following this information below

The volume of a given liquid is defined as the amount of the space occupied by the liquid that fully spreads to fill the storage place in which it is kept. The mass present per unit volume is known as density. 

Given data: 

Mass of empty pycnometer is 51.870 g. 

Mass of pycnometer when filled with liquid 1 is 86.313 g. 

Volume of pycnometer is 39.24 mL.

Calculations

The mass of liquid 1 can be calculated as shown below: 

Mass of liquid 1===(Mass of pycnometer when filled with liquid 1)−(Mass of empty pycnometer)86.313−51.87034.443 gMass of liquid 1=Mass of pycnometer when filled with liquid 1-Mass of empty pycnometer=86.313-51.870=34.443 g

Volume of liquid 1 = Volume of pycnometer 

Hence the volume of liquid 1 is 39.24 mL

Now, the density of liquid 1 can be calculated as follows: 

Density of liquid 1===Mass of liquid 1Volume of liquid 134.443 g39.24 mL0.8778 g/mLDensity of liquid 1=Mass of liquid 1Volume of liquid 1=34.443 g39.24 mL=0.8778 g/mL

Conclusion: 

Hence, the density of liquid 1 is 0.8778 g/mL .

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