From t = 0 to t = 3.46 min, a man stands still, and from t = 3.46 min to t = 6.92 min, he walks briskly in a straight line at a constant speed of 1.19 m/s. What are (a) his average velocity vavg and (b) his average acceleration aavg in the time interval 1.00 min to 4.46 min? What are (c) vavg and (d) aavg in the time interval 2.00 min to 5.46 min?

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Asked Feb 4, 2019
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From t = 0 to t = 3.46 min, a man stands still, and from t = 3.46 min to t = 6.92 min, he walks briskly in a straight line at a constant speed of 1.19 m/s. What are (a) his average velocity vavg and (b) his average acceleration aavg in the time interval 1.00 min to 4.46 min? What are (c) vavg and (d) aavg in the time interval 2.00 min to 5.46 min?

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Expert Answer

Step 1

From t=0 to t=3.46 min a man is standing still and from t=3.46 min to t=6.92 min he walks in a straight line at constant speed 1.19 m/s.

Part (a):

Total distance covered by the man in 4.46 min is,

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Step 2

Thus, total distance covered by man in 4.46min is 71.4 m.

Average velocity for time period 1.00min to 4.46 minis given by,

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Step 3

Average velocity for time period 1....

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