From the attached procedures, make a table consisting of all the compounds and their respective molecular weight (g/mol), density (g/ml), volume (ml), weight (g), mole and ratio. Take caution to ensure that the molecular weight is the CORRECT literature value.
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From the attached procedures, make a table consisting of all the compounds and their respective molecular weight (g/mol), density (g/ml), volume (ml), weight (g), mole and ratio. Take caution to ensure that the molecular weight is the CORRECT literature value.
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- (9.29 × 105/8)-20.81 = with correct sig figs2-Methylcyclohexanol (5 mL, d=0.929g g/ml, MW= 114.19) was heated under reflux with 5mL of 85% phosphoric acid. What is the theoretical yield of the product for this reaction? a) 4.5 g b) 3.9g c) 3.2g d) 2.9g e) 2.5gAg video: youtube.com/watch?v=npqooiE6DhE
- 19- A 25 mL liquid bleach sample is diluted with water to 1000 mL in a bubble gel. 25 mL of the diluted sample is transferred to the flask with a pipette, excess KI is added to it, and thus OCl- ion turns into Cl- ion and I2 is formed. The released iodine is titrated with 0.09892 M Na2S2O3 using the starch reagent, and 8.96 mL is required for the endpoint. Find the % NaOCl (w/v; w/v) in the bleach sample. (Na=23 g/mol, O= 16 g/mol, Cl = 35,44 g/mol)Lactated Ringer’s/5% Dextrose solution contains: 6 g/L of Sodium Chloride (NaCl MW 58.5) 3.1 g/L of Sodium Lactate (C3H5O3Na MW 112) 0.3g/L of Potassium Chloride (KCl MW 74.5) 0.2g/L of Calcium Chloride (CaCl2•2H2O MW 147) 50g/L of Dextrose (C6H12O6 MW 180) You receive an order to increase the Potassium ion concentration to 0.045 mEq/mL. How many mL of 14.9% Potassium chloride injection should be added to 1L of the above solution to increase the potassium ion concentration to 0.045 mEq/mL ____________________mL 14.9% KCl injectionThe ethyl acetate concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 20.00-mL portion of the diluted solution was refluxed with 40.00 mL of 0.04672 M KOH:CH3COOC2H5 + OH- → CH3COO- + C2H5OHAfter cooling, the excess OH2 was back-titrated with 3.41 mL of 0.05042 M H2SO4. Calculate theamount of ethyl acetate (88.11 g/mol) in the original sample in grams
- A 0.9092 g sample of wheat flour was analysed by the Kjeldahl procedure. The ammoniaformed was distilled into 50.00 mL of 0.02532 M H2SO4. A 7.46 mL back-titration of 0.04917 MNaOH was required. (Note the stoichiometry of your acid and base) Calculate thea. %N (FM=14.007) in the sample,b. %Protein in the sample (factor = 5.70)Given the equation of the line, y=150x-8.1221 (cells per mL is in 10^8), what is the CFU per mL of the original suspension if the thousand-fold dilution of that suspension has an absorbance of 0.3 at 600nm? *Method of separation/chemical reaction (with brief process) of 1.5 kgs cream of tartar and 2.5 kg sodium carbonate monohydrate (Seignette salt)??
- A sample of anhydrous NaHCO3 (FM = 84.007) is suspected to be contaminated with eitherNaOH (FM = 39.997) or Na2CO3 (FM = 105.989). To verify the suspicion, a 0.7483 g sample was dissolved to prepare a 50.00 mL solution, and a 10.00 mL aliquot was taken to prepare a 100 mL solution, where 25.00 mL was analyzed using double flask method. If the sample requires 0.45 mL of standard 0.0125 N HCl to reach the phenolphthalein endpoint and 35.95 mL to reach the bromcresol green endpoint, calculate the percentage composition (in %w/w) of all the basic components in the sample.Q5: If the Ksp of Ca3N2 is 6.06 x 10-3, how many moles of calcium nitride (s) could you dissolve in 1.589 L of solvent (assume that calcium nitride (s) dissolves in water to form Ca2+(aq) and N3- (aq))? Enter your answer with at least 3 sig figs. Please provide only typed answer solution no handwritten solution needed allowedA 0.9092 g sample of wheat flour was analyzed by the Kjeldahl procedure. The ammonia formed was distilled into 50.00 mL of 0.02532 M H2SO4. A 7.46 mL back-titration of 0.04917 M NaOH was required. (Note the stoichiometry of your acid and base) Calculate the a. %N (FM=14.007) in the sample, b. %Protein in the sample (factor = 5.70)