From the given continuous beam, use Three Moment equation 3q kips 2q kips 0.25q k/ft Atont -8 ft- -8 ft- -20 ft- -21-
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Solve the problem using Three Moment Equation Method. Show complete solution. Please help. Thank you!
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- Compute the reactions and draw the shear and mo-ment curves for the beam in Figure P9.21. In addition tothe applied load, the support at C settles by 0.1 m. EI isconstant for the beam. E = 200 GPa, I = 60 × 106mm4a) Compute the reaction R1 in KN. b) Compute the reaction R2 in KN. c) Compute the distance from R2 where the shear is zero in mm. d) Indicate the opening of the shear diagram cuve between R1 and R2. e) Compute the maximum positive moment in the beam in KN.m.Compute the reactions and draw the shear andmoment curves for the beam in Figure P9.19. Given: EI isconstant. Use the reactions at B as the redundants.
- Given : M1 = 400 kN-m M2 = 500 kN-m M3 = 600 kN-m P = 150 kN w1= 60 kN-m w2 = 120 kN/m a = b = d = 6 m c = 4 m Determine the following: a. The maximum positive shear (in kN). b. The maximum negative shear (in kN). c. The maximum positive moment (in kN-m). d. The maximum negative moment (in kN-m). e. The location of maximum shear from the left end of the beam (in m). f. The location of the maximum moment from the left end of the beam (in m). Kindly Draw the Shear and Moment Diagram. Compute for all of the necessary elements, Include the proper units, use the proper formula and round-off all the answers and final answers to 2 decimal places.Determine reaction at D and Moment reaction at A using conjugate beam method. Consider 150 mm x 200 (b x h) mm section and E = 80 GPa a = 2.2 m, b = 12.2 kN/m, c = 43 kNGiven : M1 = 4000 N/m M2 = 9000 N/m P = 3600 N (downward) w1= 800 N/m (downward) w2 = 600 N/m (downward) a = 4 m b = c = d = 5 m Determine the following:a. The maximum positive shear (in N).b. The maximum negative shear (in N).c. The maximum positive moment (in N-m).d. The maximum negative moment (in N-m).e. The location of maximum shear from the left end of the beam (in m).f. The location of the maximum moment from the left end of the beam (in m). Kindly Draw the detailed Shear and Moment Diagram. Compute for all of the necessary elements, Include the proper units, use the proper formula and round-off all the answers and final answers to 2 decimal places.
- 1.) What is the vertical reaction at A and B?2.) What is the horizontal and moment reaction B3.) What is the maximum positive moment in the beam?(kN-m)4.) What is the location of the maximum positive moment from point A? (m) 5.) What is the shear at a point between A and C?6.) What is the moment at a point under the concentrated load?Determine the moments at all supports. Support B settles10 mm, and EI is constant. Take E = 200 GPa, I = 200x106mm4 Answer key: MAB = -12 kN-m; MBA = 64.58 kN-m; MBC = -64.58 kN-m; MCB = -146.69 kN-m5.b) What is the reaction @ B, or RB ? 5.c) What is the reaction @ C, or RC ? 5.d) What is the reaction @ D, or RD ? 5.e) What is the maximum moment on the beam. 9 ft from A.?
- determine the reaction R1. determine the reaction R2. determine the shear at point 4meters from R1 determine the moment at point 4 meters from R1. determine the maximum moment on the beamC0nsider the frame bel0w where f0rce A = 55 N acts 0n p0int Q, f0rce B = 34 N acts on p0int P, and force C = 42 N acts on p0int M. Replace the system of f0rces acting on the frame with two f0rces, one acting on p0int O and the other acting vertically at point P. Calculate the magnitude and direction of the vertical f0rce acting on p0int P, FP, and the force acting on p0int O, FO.Determine the magnitude of the moment (Nm) of the force P = 534 N about the line DF. Round off only on the final answer expressed in 3 decimal places.