From the given information in each case below, use technology to find the P-value for a chi-square test and give the conclusion for a significance level of a = 0.01. (Use technology to calculate the P-value. Round your answers to four decimal places.) LAUSE SALT (a) x² = 7.60, df = 2 P-value= State the conclusion. O Reject Ho O Fail to reject Ho (b) x² 12.90, df = 6 P-value= State the conclusion. O Reject Ho

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From the given information in each case below, use technology to find the P-value for a chi-square test and give the conclusion for a significance level of a = 0.01. (Use technology to calculate the P-value. Round your answers to four decimal places.)
USE SALT
(a) x² = 7.60, df = 2
P-value =
State the conclusion.
O Reject Ho.
O Fail to reject Ho.
(b) x² = 12.90, df = 6
P-value =
State the conclusion.
O Reject Ho.
O Fail to reject Ho.
Transcribed Image Text:From the given information in each case below, use technology to find the P-value for a chi-square test and give the conclusion for a significance level of a = 0.01. (Use technology to calculate the P-value. Round your answers to four decimal places.) USE SALT (a) x² = 7.60, df = 2 P-value = State the conclusion. O Reject Ho. O Fail to reject Ho. (b) x² = 12.90, df = 6 P-value = State the conclusion. O Reject Ho. O Fail to reject Ho.
In a sample of 170 students at an Australian university that introduced the use of plagiarism-detection software in a number of courses, 51 students indicated a belief that such software unfairly targets students. Does this suggest that a majority of students at the
university do not share this belief? Test appropriate hypotheses at level 0.05. (Let p be the proportion of students at this university who do not share this belief.)
State the appropriate hypotheses.
Ho: p > 0.50
H₂: P = 0.50
Ho: p = 0.50
H:p> 0.50
Ho: P = 0.50
Ha: P < 0.50
O Ho: P = 0.50
H₂: P = 0.50
USE SALT
Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.)
25.22
Z =
P-value =
3 1.
X
You may have found the complement of the desired probability.
Transcribed Image Text:In a sample of 170 students at an Australian university that introduced the use of plagiarism-detection software in a number of courses, 51 students indicated a belief that such software unfairly targets students. Does this suggest that a majority of students at the university do not share this belief? Test appropriate hypotheses at level 0.05. (Let p be the proportion of students at this university who do not share this belief.) State the appropriate hypotheses. Ho: p > 0.50 H₂: P = 0.50 Ho: p = 0.50 H:p> 0.50 Ho: P = 0.50 Ha: P < 0.50 O Ho: P = 0.50 H₂: P = 0.50 USE SALT Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) 25.22 Z = P-value = 3 1. X You may have found the complement of the desired probability.
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(c) x² = 17.60, df = 9
P-value =
State the conclusion.
Reject Ho
Fail to reject Ho
(d) x² = 21.10, df = 4
P-value =
State the conclusion.
O Reject Ho.
Fail to reject Ho
(e) x² = 5.10, df = 3
P-value =
State the conclusion.
O Reject Ho.
Fail to reject Ho
Transcribed Image Text:(c) x² = 17.60, df = 9 P-value = State the conclusion. Reject Ho Fail to reject Ho (d) x² = 21.10, df = 4 P-value = State the conclusion. O Reject Ho. Fail to reject Ho (e) x² = 5.10, df = 3 P-value = State the conclusion. O Reject Ho. Fail to reject Ho
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