General, Organic and Biochemistry -Laboratory Manual 2. A student was titrating pure hydrochloric acid of unknown molarity. He forgot to take the initial volume reading for the NaOH addition in his buret and decided to assume it was 0.00 mL. His final reading on the NaOH buret was 23.45 mL, and the volume of hydrochloric acid used for titration was 25.00 mL. The molarity of the NaOH is 0.120 M. his data. Show your work: (HINT: This is a very Calculate the molarity of HCl based similar procedure for calculating excess HCI acid. Remember for the last step that molarity equals mol/L) а.

Question
General, Organic and Biochemistry -Laboratory Manual
2. A student was titrating pure hydrochloric acid of unknown molarity. He forgot to take the initial
volume reading for the NaOH addition in his buret and decided to assume it was 0.00 mL. His
final reading on the NaOH buret was 23.45 mL, and the volume of hydrochloric acid used for
titration was 25.00 mL. The molarity of the NaOH is 0.120 M.
his data. Show your work: (HINT: This is a very
Calculate the molarity of HCl based
similar procedure for calculating excess HCI acid. Remember for the last step that molarity
equals mol/L)
а.

Image Transcription

General, Organic and Biochemistry -Laboratory Manual 2. A student was titrating pure hydrochloric acid of unknown molarity. He forgot to take the initial volume reading for the NaOH addition in his buret and decided to assume it was 0.00 mL. His final reading on the NaOH buret was 23.45 mL, and the volume of hydrochloric acid used for titration was 25.00 mL. The molarity of the NaOH is 0.120 M. his data. Show your work: (HINT: This is a very Calculate the molarity of HCl based similar procedure for calculating excess HCI acid. Remember for the last step that molarity equals mol/L) а.

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