match the statements:A- Gini IndexB-InteractionsC-Dividing Gain by SplitINFOD-Misclassification ErrorE-UnderfittingTo be matched against :1-can not classify properly2- can overcome disadvantages from skewed GINI values3- model too simple4- Causes Variance5- Formula 16 - Formula 2see the picture Gini Index1- (E[P(G | t)]^2 for all j)InteractionsCan overcome disadvantage fr v[ Choose ]Dividing Gain by SplitINFOCannot classify properlyCan overcome disadvantage from skewed lower GINI values1- (E[PG| t)]^2 for all )Misclassification ErrorModel too simple1- (max(P(i| t)) for all i)Causes VarianceUnderfitting

Given some data science terms such as 1. Gini Index 2. Interactions 3. Dividing Gain by SplitINFO 4.…

Gini Index 1- (E[PG | t)]^2 for all j) Interactions Can overcome disadvantage fre v [ Choose ] Dividing Gain by SplitINFO Cannot classify properly Can overcome disadvantage from skewed lower GINI values 1- (ΣΙΡΟΙ υ2 for all ) Misclassification Error Model too simple 1- (max(P(i| t)) for all i) Causes Variance Underfitting >

Gini Index 1- (E[PG | t)]^2 for all j) Interactions Can overcome disadvantage fre v [ Choose ] Dividing Gain by SplitINFO Cannot classify properly Can overcome disadvantage from skewed lower GINI values 1- (ΣΙΡΟΙ υ2 for all ) Misclassification Error Model too simple 1- (max(P(i| t)) for all i) Causes Variance Underfitting >

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter9: Counting And Probability

Section: Chapter Questions

Problem 6P: Areas of Curved Regions the Monte Carlo method can be used to estimate the area under the graph of a...

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Areas of Curved Regions The Monte Carlo method can be used to estimate the area under the graph of a function. The figure below shows the region under the graph of f(x)=x2, above the x-axis, between x=0 and x=1. If we choose a point in the square at random, the probability that it lies under the graph of f(x)=x2 is the area under the graph divided by the area of the square. So if we randomly select a large number of point in the square, we have numberofhitsunderthegraphnumberofhitsinthesquareareaundergraphareaofsquare Modify the program from Problem 5 to carry out this Monte Carlo simulation and approximate the required area.
Population Genetics-First Cousins This is a continuation of Exercise 5. Double first cousins are first cousins in two waysthat is, each of the parents of one is a sibling of a parent of the other. First cousins in general have six different grandparents whereas double first cousins have only four different grandparents. For mating between double first cousins, the proportions of the genotypes of the children can be accounted for in terms of those of parents, grandparents, and great-grandparent: 3=122+14+18. a. Find all solutions to the cubic equation above and Identify which is 1. b. After 5 generations, what proportion of the population will be homozygous? c. After 20 generations, what proportion of the population will be homozygous? 5. Population Genetics In the study of population genetics, an important measure of inbreeding is the proportion of homozygous genotypesthat is, instances in which the two alleles carried at a particular site on an individuals chromosomes are both the same. For population in which blood-related individual mate, them is a higher than expected frequency of homozygous individuals. Examples of such populations include endangered or rare species, selectively bred breeds, and isolated populations. in general. the frequency of homozygous children from mating of blood-related parents is greater than that for children from unrelated parents Measured over a large number of generations, the proportion of heterozygous genotypesthat is, nonhomozygous genotypeschanges by a constant factor 1 from generation to generation. The factor 1 is a number between 0 and 1. If 1=0.75, for example then the proportion of heterozygous individuals in the population decreases by 25 in each generation In this case, after 10 generations, the proportion of heterozygous individuals in the population decreases by 94.37, since 0.7510=0.0563, or 5.63. In other words, 94.37 of the population is homozygous. For specific types of matings, the proportion of heterozygous genotypes can be related to that of previous generations and is found from an equation. For mating between siblings 1 can be determined as the largest value of for which 2=12+14. This equation comes from carefully accounting for the genotypes for the present generation the 2 term in terms of those previous two generations represented by for the parents generation and by the constant term of the grandparents generation. a Find both solutions to the quadratic equation above and identify which is 1 use a horizontal span of 1 to 1 in this exercise and the following exercise. b After 5 generations, what proportion of the population will be homozygous? c After 20 generations, what proportion of the population will be homozygous?
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