Given a Binary Number B, find its decimal equivalent. Example 1: Input: B = 10001000 Output: 136 Example 2: Input: B = 101100 Output: 44 Your Task: You don't need to read or print anything. Your task is to complete the function binary_to_decimal() which takes the binary number as string input parameter and returns its decimal equivalent. Expected Time Complexity: 0(K * Log(K)) where Kis number of bits in binary number.
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- In a scheduling program, we want to check whether two appointments overlap. For simplicity, appointments start at a full hour, and we use military time (with hours 0–24). The following pseudocode describes an algorithm that determines whether the appointment with start time start1 and end time end1 overlaps with the appointment with start time start2 and end time end2.If start1 > start2s = start1Elses = start2If end1 < end2e = endl Elsee = end2 If s < eThe appointments overlap.Else The appointments don’t overlap.Trace this algorithm with an appointment from 10–12 and one from 11–13, then with an appointment from 10–11 and one from 12–13.On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements.On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements. Ex: If the input is: 440.0 (which is the A key near the middle of a piano keyboard), the output is: 440.00 466.16 493.88 523.25 554.37 Note: Use one statement to compute r = 2(1/12) using the pow function (remember to include the cmath library). Then use that r in subsequent statements that use the formula fn = f0 * rn with n being 1, 2, 3, and finally 4.
- On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements. Ex: If the input is: 440.0 (which is the A key near the middle of a piano keyboard), the output is: 440.00 466.16 493.88 523.25 554.37 Note: Use one statement to compute r = 2(1/12) using the pow function (remember to include the cmath library). Then use that r in subsequent statements that use the formula fn = f0 * rn with n being 1, 2, 3, and finally 4. I am having trouble putting them on one sentence line.I need help with creating a Java program described below: Hamming distance. The Hamming distance between two-bit strings of length n is equal to the number of bits in which the two strings differ. Write a program that reads in an integer k and a bit string s from the command line, and prints all bit strings that have Hamming distance at most k from s. For example, if k is 2 and s is 0000, then your program should print 0011 0101 0110 1001 1010 1100 Hint: Choose k as the number of bits to flip in s.I need to write a recursive Java program to count the number of muck-free regions in a lagoon. The Lagoon is represented by a rectangle of N x M squares. Each square contains either muck ('M') or sand ('.'). A region is defined as a connected set of one of more squares with sand in it, where a square is considered to connect to all eight of its adjacent squares. Sample input/output is shown in picture attached
- A finite sequence of symbols from a given alphabet will be called a string over the alphabet. A string that consists of a sequence a1, a2, a3, a4, … … … … , an of symbols will be denoted by the juxtaposition a1 a2 a3 a4 … … … … an. Given the strings: u = a2bab2and v = bab2, Evaluate the following operations for strings: (i) ԑu(ii) u + v(iii) u(u| v)(iv) v | (v | u)Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply divide-and-conquer algorithm in the problem. Make sure all test cases return expected outputs by providing output screenshots. Provide screenshots Hint: Apply bisection method/modules Output FormatOutput contains a line with two space-separated integers W_a and W_b.- W_a is the maximum matchups won by Hamiltonia- W_b is the maximum matchups won by Burrgadia. Sample Input 03 554402410 Sample Output 03 0 Sample Input 15 4833485183 Sample Output 12 2 Sample Input 27 81028121912601319851 Sample Output 27 0 The actual code """Solves a test case Parameters:a : int - number of leaders in Hamiltoniab : int - number of leaders in Burrgadias_i : array-like - rap proficiencies of Hamiltonia's leadersr_j : array-like - rap proficiencies of…Computer Science you are given a string X of length n and another string Y of length m ≤n. Say,the indexes p1, p2, p3, p4 and q1, q2, q3, q4 form two sub-sequences, i.e., 0 ≤ p1 < p2 < p3 < p4 < nand 0 ≤q1 < q2 < q3 < q4 < n; then, they are non-overlapping if p4 < q1.The task is to count the maximum number of non-overlapping sub-sequences of X that are thesame as Y . Thus, if X = GAXTYAWBGTAUGBTABGRGTAXB and Y = GTAB, then the answer is3 as shown by the red fonts. We cannot select the underlined GTAB as it overlaps with a red GTAB(i.e., among overlapping sub-sequences, you can select only one of them).Describe an O(m + n) time algorithm to obtain the count. Write a pseudo-code.