Given a functor parameterised type m and comes with a function return :: a -> m a, show how functions with the following types can each be defined in term of the other: (>>=) :: m a -> (a -> m b) -> m b combine :: m (m a) -> m a
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Given a functor parameterised type m and comes with a function return :: a -> m a, show how functions with the following types can each be defined in term of the other:
(>>=) :: m a -> (a -> m b) -> m b
combine :: m (m a) -> m a
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- A normal function typically does not store data, while functors can preserve information in its member variables. is it true or falseDesign a class ProblemSolution to overload a function solution. Write a function int solution(int N, char CH) that accepts integer N and character CH. The function should return square of a number (N) if a character (CH) is "s" otherwise return cube of a number. int solution(int N, int M, char CH) that accepts two integers (N and M) and one character CH. The function should return the product of two integers if a character (CH) is ‘p’ otherwise return their sum. boolean solution(String S1, String S2) that accepts two strings S1 and S2. The function should return true if S1 and S2 are equal otherwise false. Input 1 4 s where, First line represents a choice for calling one of the defined methods. (1 for solution(int N, char CH), 2 for solution(int N, int M, char CH) and 3 for solution(String S1, String S2)). Second line represents number input. Third line represents choice CH. Output 16 Here, the first line contains 1 and hence solution(int N, char…In c++, write a function Circle::intersect(Circle c) where class is defined below, for the funtion it returns bool values, true if two circle outline intersect each other and false if not. Circle::intersect(Circle c) { // example double X = x - c.getX(); double Y = y - c.getY(); double rad = radius + c.getRadius(); } class Circle { private: double x; double y; double radius; public: bool intersect(Circle c); }
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- Computer Science Consider the following defintion: data Term = Var String | Application Term Term | Lambda String Term Construct a Haskell function: alphaRename :: Term -> String -> Term Where it performs an alpha renaming. (alphaRename t x) substitutes x for the formal parameter of t, which must be a lambda expression. You can assume that x is not free in t, i.e., not free in the body of t. Please provide your function code with an example input for the above operation.Template functions are considered to be an efficient alternative of function overloading. Justify this statement by comparing the pros and cons of both with real-world examples.Consider the following defintion: data Term = Var String | Application Term Term | Lambda String Term Construct a Haskell function: alphaRename :: Term -> String -> Term Where it performs an alpha renaming. (alphaRename t x) substitutes x for the formal parameter of t, which must be a lambda expression. You can assume that x is not free in t, i.e., not free in the body of t. Please provide your function code with an example input for the above operation.
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