Given a function with one vector parameter scores. How should the parameter be defined if scores may by very large and the function will modify the parameter? A) constant, and pass by value B) not constant and pass by value C) not constant and pass by reference D) constant and pass by reference

Consider the following function shoots : def shoots(x: int) -> int: if x <= 0: return 0 4 elif x == 1: return shoots(x + 2) 6 elif x == 2: return shoots(x - 1) 80 elif x == 2: 9. return -1 10 else: 11 return shoots(x - 2) 2 3

For each of the following expressions, write functions f1, f2, f3, and f4 such that the evaluation of each expression succeeds, without causing an error. Be sure to use lambdas in your function definition instead of nested def statements. Each function should have a one line solution. f1 takes in nothing and returns 3. f2 takes in nothing and returns a function that takes in nothing and returns 3. f3 takes in nothing and returns a function that takes in 1 value and returns that same value. f4 takes in nothing and returns a function. This function takes in nothing and returns another function. This next function takes in a value and returns yet another function. This final function takes in nothing and returns the value passed into the previous function (if this explanation is confusing, have a look at the doctest, and it might be more clear). def f1(): >>> f1() 3 |||||| "*** YOUR CODE HERE ***" def f2(): |||||| >>> f2() () 3 |||||| "*** YOUR CODE HERE ***" def f3(): |||||| >>> f3() (3)…

Redesign the solution using functions. For this lab: 1. You will define a function named main() (LO 1) 2. You will get input in the main function and pass it to the following functions: (LO 2) a. milesToKm() b. FahToCel() c. GalToLit() d. PoundsToKg() e. InchesToCm() 3. Each function will require that you have a local variable to store the result of the calculation. This result will then be displayed using the print statement from within the function