Given a process with address space of size 32 bytes and page size of 8 bytes, if the CPU asks to access a variable in page 1 using offset 2: What is the physical address of this variable in main memory? Page Table Page Frame 6 1 3 7 O 50 O 40 O 16 O 26 2.
Q: Consider a logical address space of 16 pages of 8192 words each, mapped onto a physical memory of…
A: Logical memory has 16 pages and each of those pages has 8192 words. In order to address every one of…
Q: If a program has 956 bytes and will be loaded into page frames of 150 bytes each, and the…
A:
Q: A virtual memory has a page size of 2K(words). There are eight pages and four blocks. The…
A: Here page size = 2K words Thus page offset bits is 11 bits Total number of pages=8 Thus page number…
Q: Given a computer using a byte-addressable virtual memory system with a two-entry TLB, a 2-way set…
A:
Q: Suppose we have a computer system with a 44-bit virtual address, page size of 64 KB. How many pages…
A: Virtual address size = 44 bits Page size = 64KB Page offset bits =log2 64KB = 16 bits So page number…
Q: Suppose that a machine provides instructions that can access memory locations using the one-level…
A: The page fault is the interruption which occurs when the software program attempts to access the…
Q: 1. Suppose a process page table contains the entries shown below. Using the format shown in Figure…
A: Over here we have asked how virtual memory mapped to physical memory.
Q: Time left Given a process with address space of size 32 bytes and page size of 8 bytes, if the CPU…
A:
Q: A computer with a 32-bit address uses a two-level page table. Virtual addresses are split into a…
A: The ask is to calculate the page size and numbr of pages in the address space for a computer with a…
Q: In a page addressing system of 15 bits, where eight bits are used for the page number, what would be…
A: The above question is solved in step 2 :-
Q: Suppose the page table for process B that is currently executed on the processor is as in Table 1.…
A: List the logical address ranges for each page. Given the following new ordered page…
Q: b. Suppose we use two-level paging and arrange for all page tables to fit into a single page frame.…
A:
Q: Consider a system with 39-bit virtual addresses, 44-bit physical addresses, 4096 byte pages, and the…
A: The answer is
Q: Time left Given a process with address space of size 32 bytes and page size of 8 bytes, if the CPU…
A:
Q: Suppose a process page table contains the entries shown below. Using the format shown in Figure…
A: The process pages are located as follows:
Q: Consider the virtual memory scheme using paging. The page size is 128 bytes. The entries in the page…
A: In this case, the machine is a 16-bit system with a 4KB page size and 64KB of physical memory.…
Q: consider a computer system using paging to manage memory; suppose it has 64K (2-) bytes of memory…
A:
Q: Suppose the page table for the process currently executing on the processor looks like the…
A:
Q: Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses. (a) What is the…
A: Given Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses.(a) What is…
Q: Suppose that the offset field of a byte-addressed 32-bit paged logical address is 12 bits. Then, a…
A: 1) Byte addressable 32-bit system can accomodate 232 bytes = 4,294,967,296 bytes 2) 12- bit logical…
Q: What are the physical addresses for the following logical address your work A) 3 B) 9 C) 14 Consider…
A: Page size is 4 Bytes. So page offset is 2 bits. 1. Logical address = 3 = 00011 Page offset is 11…
Q: We have a paged virtual address system with the maximum size of virtual address space of 32 MB. The…
A: As per answering guidelines solving the first 3 sub question completely. A) Number of bits for…
Q: Time left n 13 Given a process with address space of size 32 bytes and page size of 8 bytes, if the…
A: Introduction
Q: Given a 32-bit virtual address space featuring a 10-10-12 split and a 4-byte PTE size, suppose a…
A: The memory is split as 10 - 10 - 12 This means page size is 4KB. Now process size is 9MB Therefore…
Q: Consider the following portion of a page table from a system with 4 KiB (i.e., 4096 byte) pages.…
A: We have given portion of page table and page size is 4KiB. Using virtual memory address, we have to…
Q: Consider a machine where total addressable physical memory size is 32 Kbytes. If we would like to…
A: total addressable physical memory size=32 Kbytes. we like to run 2 processes P and R as 8KB using…
Q: Consider a machine where total addressable physical memory size is 32 Kbytes. If we would like to…
A: given, physical mem size=32 p=8KB R=2KB
Q: Given a process with address space of size 32 bytes and page size of 8 bytes, if the CPU asks to…
A:
Q: Consider a computer system with 32-bit virtual addressing and a page size of sixty-four kilobytes.…
A: In this question, we are given virtual address and physical memory size and also page size. Page…
Q: Given a process with address space of size 32 bytes and page size of 8 bytes, if the CPU asks to…
A: As we know Physical address = page size*frame number + offset
Q: The PowerPC uses a hardware managed TLB with an inverted page table. Discuss its advantages and…
A: Given: The PowerPC uses a hardware managed TLB with an inverted page table. Discuss its advantages…
Q: Q3 The program size = 16, and page size 2^2, find the physical address in the following: 1) page 0…
A: Answer
Q: Let's assume a system has 64 bytes of physical memory, 4 byte pages, and 16-byte virtual address…
A: The information given are : Physical memory size = 64 bytes Size of page = 4 bytes Size of virtual…
Q: Consider a logical address space of 256 pages of 1024 words each. This is mapped onto a physical…
A: Given: logical address space= of 256 pages of 1024 words each. the physical memory=32 frames. We…
Q: Assuming memory frame size = process page size = 1024, what physical address will logical address…
A: Given that, Main memory frame size= process page size= 1024 Logical address= 2076 To get physical…
Q: a) A paging system with 512 pages of logical address space, a page size of 2* and number of frames…
A:
Q: In a 12-bit machine with page size of 128, we have a physical address of 1000 1001 1011. What is the…
A: Given physical address=100010011011=2203 Page size=128
Q: Consider a system with 16-bit virtual addresses, 256 byte pages, and 4 byte page table entries. The…
A: PTE's per process = 216/28=28 PTE's per page = 28/22 = 26.
Q: Consider a computer system with a 24-bit logical address and a 28-bit physical address. Let's…
A: logical address space = 224 physical address space = 210
Q: Consider a paged virtual memory system with 12 bit virtual addresses & IKB pages Each page table…
A: The answer for number of levels page tables are
Q: Suppose a computer using fully associative cache has 2^24 bytes of byte-addressable main memory and…
A: Full associative cache size=224 bytes.Size of each block=64 bytesBlocks of main memory=cache…
Q: Given a virtual memory of size 4 GiB, physical memory of size 1 GiB, and page size equal to 256 KiB.…
A: Here in this question we have given Virtual memory size = 4GiB Physical memory size = 1GiB Page size…
Q: Consider a computer system with a 64-bit logical address and 32-KB page size. The system supports up…
A: 2) Consider a computer system with a 64-bit logical address space and 2-KiB page size. The system…
Q: Given a page table and a logical address=0002022H, where is it physically (what is its physical…
A: As per our guidelines we are supposed to answer?️ only one question. Kindly repost other questions…
Q: Given a computer using a byte-addressable virtual memory system with a two-entry TLB, a 2-way set…
A: Below is the answer with explanation and calculation:
Q: Take a look at a 64-bit logical address space. a. Assuming a page size of 4 KB Discover the truth.…
A: Introduction: the question is about Take a look at a 64-bit logical address space. a. Assuming a…
Q: In the following three questions, assume a 32-bit virtual address space and page size equal to 4096…
A: Given: Virtual address space = 32 bit page size = 4096 bytes To find: Number of page table entry
Q: Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a…
A: The computer has the fully associative cache with cache files of 128 blocks A fully associative…
q24
Step by step
Solved in 2 steps with 1 images
- Consider an operating system using memory mapping on a page basis and using a single level page table. Assume that the necessary page table is always in memory. The system takes 200 ns to make a memory reference, how long does a paged memory reference take? Group of answer choices 400 ns (nanoseconds) 809.2 ms (microseconds) 200 ns (nanoseconds) 1638.4 ms (microseconds)A system with simple paged memory management has addresses of B bits and pages of size P KiB. If all memory is pageable, what is the maximum number of items contained in a process's page table? What if K KiB are reserved for the kernel and are not pageable? Also suppose that the page table is organized in 2 levels, so that the page directory (first level) is addressed by D bits. How many bits will be used to address the second level? How many entries will there be, at most, among all the tables of the pages (first and second level) of a process?Assume a process containing 5 pages with 1024 bytes per page and physical memory with 10 page frames. Frames and pages are of the same size. Given the following page map table (PMT): a) determine the physical address associated with the logical address of page 1, offset 100? b) what is the logical address associated with the physical address 2300? Please dont over complicate this question!!
- Suppose the page table for the process currently executing on the processor looks like the following. All numbers are decimal, everything is numbered starting from zero, and all addresses are memory byte addresses. The page size is 1,024 bytes. Virtual page number 0 Valid bit Reference bit Modify bit Page frame number 1 1 0 1 1 7 2 0 0 0 3 1 0 0 2 4 0 0 0 5 1 0 1 0 What physical address, if any, would each of the following virtual addresses correspond to? (Do not try to handle any page faults, if any.) 1,052 2,221 5,499 Edit View Insert 12pt Paragraph Format Tools Table BIU AvConsider a system with 256Mbytes of main memory with page size of 4Kbytes. It has a logical address space of 26-bits. Answer the following questions. (Assume byte-addressable memory) (i) How many of the 26-bits of the logical address represent page# and how many bits represent the offset? (ii) How many entries are there in a conventional single-level page table for a process? (iii) How many entries are there in an inverted page table?A virtual memory has a page size of 2K(words). There are eight pagesand four blocks. The associative memory page table contains the followingentries:Page Block0 32 15 26 0Make a list of all virtual addresses (In decimal) that will cause a page fault if used by the CPU.
- A computer with a 32-bit address uses a two-level page table. Virtual addresses are split into a 9-bit top-level page table field, an 11-bit second-level page table field, and an offset. How large are the pages and how many are there in the address space?Suppose you have a byte-addressable virtual address memory system with 32 virtual pages of 32 bytes each, and 8 page frames. Assuming the following page table, answer the questions below: | Page # | Frame # | Valid bit ||--------|---------|-----------|| 0 | 4 | 1 || 1 | 3 | 1 || 2 | - | 0 || 3 | 0 | 0 || 4 | 1 | 1 || 11 | 6 | 0 || 13 | 7 | 1 || 17 | - | 0 | a) How many bits are needed to address this virtual memory? b) What is the size of the Page field? c) What is the size of the Offset field? d) What is the size of the Page Frame field? e) What is the maximum number of the entries in this Page Table? f) What Physical address corresponds to the Virtual address 0x22? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page fault" with the proper reason) g) What Physical address corresponds to the…Suppose you have a byte-addressable virtual address memory system with 32 virtual pages of 32 bytes each, and 8 page frames. Assuming the following page table, answer the questions below: | Page # | Frame # | Valid bit ||--------|---------|-----------|| 0 | 4 | 1 || 1 | 3 | 1 || 2 | - | 0 || 3 | 0 | 0 || 4 | 1 | 1 || 11 | 6 | 0 || 13 | 7 | 1 || 17 | - | 0 |a) How many bits are needed to address this virtual memory? b) What is the size of the Page field? c) What is the size of the Offset field? d) What is the size of the Page Frame field?
- . Suppose we have 2 bytes of virtual memory and 28 bytes of physical main memory. Suppose the page size is 24 bytes.Q.) How many entries are in the page table for a process that uses all of virtual memory?An operating system designed for an embedded system application needs to manage a process of size 512KB with a page size of 8KB. If the memory size is 256KB then answer the following questions - a) Determine the minimum number of bits required to manage the logical address space. b) Determine the minimum number of bits required to manage the physical address space.Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB. Answer the following questions, assuming a virtual address 0x00030f40 A. What is the virtual page number (VPN) and the offset in binary for the given virtual address? B. How many virtual pages are there in the system?