Given a Singly Linked List, write a function reverse() that reverses the list. Also determine the complexity of your function in terms of Big-Oh notation. While reversing the list, you must not use any additional list or arrays. For example, the given list is: head → 1→2→3→4→ 5→ NULL The output should be: head → 5→ 4 → 3 → 2→ 1→ NULL While writing the function, consider the following Node class. class Node{ public: int key; Node* next;

Given a Singly Linked List, write a function reverse() that reverses the list. Also determine the complexity of your function in terms of Big-Oh notation. While reversing the list, you must not use any additional list or arrays. For example, the given list is: head → 1→2→3→4→ 5→ NULL The output should be: head → 5→ 4 → 3 → 2→ 1→ NULL While writing the function, consider the following Node class. class Node{ public: int key; Node* next;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Finally, we will do some simple analysis – ranking of words. Write a function word_ranking(corpus, n, sort_index) which takes input parameters corpus (type list), n (type int), and sort_index (type int) and returns a list containing tuples of words and their frequencies in the top n of words. Here, corpus is a list of sentences. n is the number of ranked words to return. The resulting list should then be sorted based on the sort_index; sort_index = 0 should sort the list of tuples in ascending alphabetical order, while sort_index = 1 should sort the list of tuples by the frequencies in descending order. All other numeric values for sort_index should return an empty list (don't need to consider non-integer inputs). For example, we have: corpus = ['hi hi hi hi', 'hello hello say bye', 'bye bye']n = 3sort_index = 1 The function should return: [('hi', 4), ('bye', 3), ('hello', 2)] While sort_index = 0 should return: [('bye', 3), ('hello', 2), ('hi', 4)] You can assume n would…
Computer Science please solve this problem as soon as possible Write a function to insert the element into the linked list the given number X. E.g., for a given set of integers, [2, 4, 12, 6, 5, 3], the linked list is 2->4->12->6->5->3. For a given number, (X=15), the count will be 11 that are (2,4), (2,12), (2,6), (2,5), (2,3), (4,6), (4,5), (4,3), (6,5), (6,3), (5,3).
I want to reduce the amount of line i have in these functions , meaning i want to rewrite then in a shorter version(list comprehension and mapping can be used. def prioritize(self): l = len(self.queue) for index in range(0, l): for i in range(0, l-index-1): if (self.queue[i] > self.queue[i + 1]): d = self.queue[i] self.queue[i] = self.queue[i +1] self.queue[i +1]= d def astarprioritize(self): l = len(self.queue) for index in range(0, l): for i in range(0, l-index-1): if (self.queue[i].compare(self.queue[i + 1])): d = self.queue[i] self.queue[i] = self.queue[i +1] self.queue[i +1]= d
The function Ecol_M M in the Python programme that implements this approach discovers the minimum edge colours for a graph that is passed to it in the form of an incidence matrix. To discover the maximal matching in the graph, we utilise the Maximal Match function from the earlier constructed module MATCH within this function. The list edges is used to retain uncolored edges, while the list edge color is used to hold the current edge colours. The while loop continues to run until the edges list is empty, at which point all edges have been coloured. At each iteration, the graph is reduced by removing the columns associated with the matched edges.
Let T : P −→ L be a function that inputs a perfect binary tree and outputs a list of vertices, defined as follows. B. If X is a binary tree consisting only of a single vertex v, then T (X ) = v, a list with only one entry. R. If X is a binary tree with root v, left subtree Xl and right subtree Xr , then T (X ) equals the list T (Xl ), T (Xr ), v.
Write a function(in pyhton) that takes a list of distinct integers l, and an integer k. Your function then finds the index of the integer in l, whose removal from l results in a list whose sum is k. For example, given [3,6,4,1,5,2] and 18, your function should return index 0, which corresponds to 3 in the list. Because, when 3 is removed from the list, the sum of the remaining list [6,4,1,5,2] is 18. You can assume that the given problem is always solvable.
Given the head of a singly linked list of integers, write the function to arrange the elements such thatall the even numbers are placed after all the odd numbers. The relative order of the odd and eventerms should remain unchanged.Input Format:Elements of linked listOutput Format:Resultant linked listSample Input 1:1 4 5 2Sample Output 1:1 5 4 2Sample Input 2:1 11 3 6 8 0 9Sample Output 2:1 11 3 9 6 8 0 in java
We assume that the nodes of the singly linked lists are organized in decreasing order of the exponents of the variable x in order to add the two polynomials.The goal is to build a fresh list of nodes to symbolize the addition of P1 and P2. This is accomplished by combining the COEFF fields of the nodes in lists P1 and P2 that have similar powers of the variable x, then adding a new node that reflects this action in the resulting list P1 + P2. The key steps of the process are presented below.Here, P1 and P2 are the single-linked lists that symbolize the polynomials P1 and P2, respectively. Furthermore, two temporary pointers named PTR1 and PTR2 have their initial values assigned to P1 and P2, respectively. Script out the process code
Define a function compress : lists(T) → lists(T) that accepts a list argument (of some generic type T) and returns a list without any subsequent redundancies, e.g. compress(⟨a, a, b, b, b, c, c, a, b⟩) = ⟨a, b, c, a, b⟩ 1. Transform the definition into a computable function.2. Define f recursively.3. Unfold your definition for compress(⟨a, a, b, b, c, a⟩).4. (PROGRAMMING) Please map your definition into a Common LISP function. Place your code in file compress.lisp. The code should behave as follows: > (compress ’(a a a b c d d e))(A B C D E)> (compress ’())NIL> (compress ’(a b c c c a))(A B C A)> (compress ’(a a b b c c c c a b b))(A B C A B)
To add the two polynomials, we assume that the singly linked lists' nodes are organized in decreasing order of the variable x's exponents.The goal is to generate a new list of nodes reflecting the sum of P1 and P2. This is accomplished by combining the COEFF fields of nodes with comparable powers of variable x in lists P1 and P2, and then adding a new node in the resultant list P1 + P2. The procedure's core is presented below.P1 and P2 are the beginning pointers of the singly linked lists that symbolize polynomials P1 and P2. Furthermore, PTR1 and PTR2 are two temporary pointers that are originally set to P1 and P2, respectively. Procedure code should be written.
Write a function, to be included in a sorted linked list class, called printPosition, that will receive a T parameter and print its position within the list ( position 1 if in first node, position 2 if in second…). If the item is not in the list, specify it in a printing. Consider efficiency.
Given two binary trees with head reference as T and S having at most N nodes. The task is to check if S is present as subtree in T.A subtree of a tree T1 is a tree T2 consisting of a node in T1 and all of its descendants in T1 You don't need to read input or print anything. Your task is to complete the function isSubtree() that takes root node of S and T as parameters and returns 1 if S is a subtree of T else 0. Expected Time Complexity: O(N).Expected Auxiliary Space: O(N). Constraints:1 <= Number of nodes <= 1051 <= Value of nodes <= 104