Question
Asked Oct 10, 2019
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Given a solution of NaOH in Water that has a molarity of .04M, that contains .08 g of NaOH or .002 mol NaOH.  This is all in a 50 mL container.

How many hydroxide ions (OH-) are present in this solution?

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Step 1

Solution stoichiometry involves the calculation of concentration of solutions in the given conditions of volumes, moles etc.

Step 2

Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, volume and molarity is as given below;

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Moles of solute Molarity volume of solution in L Mass of solute in g Moles Molar mass of solute (g/mol)

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Step 3

NaOH is a strong base which can easily ionized ...

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NaOH >Na (a)+OH (aq) (aq)

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