Given: Ca2+(aq) + 2e → Cd(s) EO = -0.40 V %3! Co2+(aq) + 2e Co(s) EO = -0.28 V Calculate the equilibrium constant, K, at 25°C for the reaction: Col(s) + Ca2*(aq) => Co2+(aq) + Cd(s) Gas constant = 0.0821 L.atm/mol.K = 8.314 J/mol.K & Faraday constant = 96500 C/mol e. OA. 1.14x104 B. 1.04x10-23 c. 8.80x10-5 D. 9.60x1022

Principles of Modern Chemistry
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ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 106CP
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Given:
Cd2+(aq) + 2e → Cd(s)
EO = -0.40 V
Co2+(aq) + 2e" → Co(s)
EO = -0,28 V
Calculate the equilibrium constant, K, at 25°C for the reaction:
Co(s) + Cd2+(aq) <=> Co2+(aq) + Cd(s)
Gas constant = 0.0821 L.atm/mol.K = 8.314 J/mol.K & Faraday constant = 96500 C/mol e".
DA. 1.14x104
в. 1.04х1023
c. 8.80x10-5
D. 9.60x1022
Transcribed Image Text:Given: Cd2+(aq) + 2e → Cd(s) EO = -0.40 V Co2+(aq) + 2e" → Co(s) EO = -0,28 V Calculate the equilibrium constant, K, at 25°C for the reaction: Co(s) + Cd2+(aq) <=> Co2+(aq) + Cd(s) Gas constant = 0.0821 L.atm/mol.K = 8.314 J/mol.K & Faraday constant = 96500 C/mol e". DA. 1.14x104 в. 1.04х1023 c. 8.80x10-5 D. 9.60x1022
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