Note: Round off only in the final answer (Use 4 decimal places) A footing supports a 250 mm thick concrete wallGiven:Service Axial Load = 380 kN/m%3DConcrete, f'c = 20 MPaSteel, fy = 415 MPaWidth of Footing 2.16 mThickness of Footing = 300 mmCohesion = 15.21 kPaUnit weight of soil = 17.44 kN/m3%3DSaturated unit weight of soil = 21.46 kN/m3Depth of the footing = 1.52 meter%3DDepth of GWT from the bottom of footing = 0.74 meterFriction angle = 20 degrees%3DCalculate the gross factor of safety, Use Terzhagi's bearing equation.

Given: A wall footing of width 2.16 m is resting a a depth of 1.52 m as shown below Properties of…

Given: Service Axial Load = 380 kN/m %3D Concrete, f'c = 20 MPa Steel, fy = 415 MPa Width of Footing = 2.16 m Thickness of Footing = 300 mm %3D Cohesion = 15.21 kPa Unit weight of soil = 17.44 kN/m3 Saturated unit weight of soil = 21.46 kN/m3 %3D Depth of the footing = 1.52 meter %3D Depth of GWT from the bottom of footing = 0.74 meter Friction angle = 20 degrees Calculate the gross factor of safety, Use Terzhagi's bearing equation.

Given: Service Axial Load = 380 kN/m %3D Concrete, f'c = 20 MPa Steel, fy = 415 MPa Width of Footing = 2.16 m Thickness of Footing = 300 mm %3D Cohesion = 15.21 kPa Unit weight of soil = 17.44 kN/m3 Saturated unit weight of soil = 21.46 kN/m3 %3D Depth of the footing = 1.52 meter %3D Depth of GWT from the bottom of footing = 0.74 meter Friction angle = 20 degrees Calculate the gross factor of safety, Use Terzhagi's bearing equation.

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter9: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 9.15P

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