Given: Single-stage, voltage-divider biased, common-emitter with 1. VCC = 14V 2. R1 = 32kohms 3. R2 = 7kohms 4. RC = 2kohms 5. RE = 1kohms 6. RS = 10ohms 7. RL = 2kohms 8. BDC = BAC = 135 9. ** 10. C, andC2 are coupling capacitors. 11.Cz is bypass capacitor 12. 13.Solve for: a. VB = Blank 1 V; b. VE = Blank 2 V ; c. IE = Blank 3 mA; d. VCE = Blank 4 V ; e. VC = Blank 5 V; f. re' = Blank 6 ohms ; g. Rin(base) = Blank 7 kohms; h. Rin(tot) = Blank 8 kohms ; i. Voltage gain (Av) = Blank 9 ; j. Attenuation (Att) = Blank 10 ; k. Overall voltage gain (AVT) = Blank 11;

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
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answer 7-9 only

Given:
Single-stage, voltage-divider biased, common-emitter with
1. VCC = 14V
2. R1 = 32kohms
3. R2 = 7kohms
4. RC = 2kohms
5. RE = 1kohms
6. RS = 10ohms
7. RL = 2kohms
8. BDC = BAC = 135
9. **
10.C, andC2 are coupling capacitors.
11.Cz is bypa
сараcitor
12.
13. Solve for:
a. VB = Blank 1 V;
b. VE = Blank 2 V;
c. IE = Blank 3 mA;
d. VCE = Blank 4 V ;
e. VC = Blank 5 V;
f. re' = Blank 6 ohms ;
g. Rin(base) = Blank 7 kohms ;
h. Rin(tot) = Blank 8 kohms ;
i. Voltage gain (Av) = Blank 9 ;
j. Attenuation (Att) = Blank 10;
k. Overall voltage gain (AVT) = Blank 11;
Transcribed Image Text:Given: Single-stage, voltage-divider biased, common-emitter with 1. VCC = 14V 2. R1 = 32kohms 3. R2 = 7kohms 4. RC = 2kohms 5. RE = 1kohms 6. RS = 10ohms 7. RL = 2kohms 8. BDC = BAC = 135 9. ** 10.C, andC2 are coupling capacitors. 11.Cz is bypa сараcitor 12. 13. Solve for: a. VB = Blank 1 V; b. VE = Blank 2 V; c. IE = Blank 3 mA; d. VCE = Blank 4 V ; e. VC = Blank 5 V; f. re' = Blank 6 ohms ; g. Rin(base) = Blank 7 kohms ; h. Rin(tot) = Blank 8 kohms ; i. Voltage gain (Av) = Blank 9 ; j. Attenuation (Att) = Blank 10; k. Overall voltage gain (AVT) = Blank 11;
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