Given:TABLE 3.1. Coefficients forRectangular Bars in TorsionC20.1406O.16610,19580.2290.2080.2190.2310.2460 2580.2670.2820.29110121.5200.2490.2630.2810.2910.3120.333304.05.010,00312000.333Wood:Allowable stress: 5 MPaShear Modulus: 0.5 GPaL= 0.6 md = 50 mm What is the largest safe torque, in Nm, can be applied to the circular cross-section? (Provide answer in whole numbers, without the units. Ex: 123.4 Nm -->123)Your answerWhat is the largest safe torque can be applied to the rectangular cross-section?(Provide answer in whole numbers, without the units. Ex: 123.4 Nm --> 123)Your answer

Answered: Image /qna-images/answer/078b0d3c-a257-434a-a29e-4630699fc95b.jpg

Given: TABLE 3.1. Coefficients for Rectangular Bars in Torsion C2 0.208 0.219 0.231 0.246 0258 0.267 0.282 0.291 0.1406 0.1661 0,1958 0.229 0.249 0.263 0.281 0.291 0.312 0.333 10 12 15 2.0 30 4.0 5.0 10.0 0.312 00 0.333 Wood: Allowable stress: 5 MPa Shear Modulus: 0.5 GPa L= 0.6 m d = 50 mm

Given: TABLE 3.1. Coefficients for Rectangular Bars in Torsion C2 0.208 0.219 0.231 0.246 0258 0.267 0.282 0.291 0.1406 0.1661 0,1958 0.229 0.249 0.263 0.281 0.291 0.312 0.333 10 12 15 2.0 30 4.0 5.0 10.0 0.312 00 0.333 Wood: Allowable stress: 5 MPa Shear Modulus: 0.5 GPa L= 0.6 m d = 50 mm

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Given:
TABLE 3.1. Coefficients for
Rectangular Bars in Torsion
C2
0.1406
O.1661
0,1958
0.229
0.208
0.219
0.231
0.246
0 258
0.267
0.282
0.291
10
12
1.5
20
0.249
0.263
0.281
0.291
0.312
0.333
30
4.0
5.0
10,0
0312
00
0.333
Wood:
Allowable stress: 5 MPa
Shear Modulus: 0.5 GPa
L= 0.6 m
d = 50 mm

What is the largest safe torque, in Nm, can be applied to the circular cross-
section? (Provide answer in whole numbers, without the units. Ex: 123.4 Nm -->
123)
Your answer
What is the largest safe torque can be applied to the rectangular cross-section?
(Provide answer in whole numbers, without the units. Ex: 123.4 Nm --> 123)
Your answer

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