Given that the main memory size is 32KB, the page size is 64B, the word size is 1B, and n-level paging is applied. What is the page number size?  If (5, 10) is a record in the outer page table stored in PCB and (9, 7) is a record in the inter page table stored in page frame No.10, what is the physical address of the logical address  0010101001000110 in HEX?

Q: Suppose there is a paging system with a translation lookaside buffer. Assuming that the entire page…

A:

Q: Flash storage: Suggest how to reduce the size of the translation table if very often long ranges of…

A: EXPLANATION: Flash storage is a non-volatile memory chip used for storage and used for transferring…

Q: Consider a logical address space of 8 pages of 1024 words mapped into memory of 32 frames. How many…

A: Introduction :Given , Logical address space = 8 pages size of a page = 1024 wordsmemory size = 32…

Q: Consider a paging system with the page table stored in memory. a. If a memory reference takes 50…

A: The Answer is in step2

Q: Given a computer using a byte-addressable virtual memory system with a two-entry TLB, a 2-way set…

A:

Q: Consider a computer system with a 24-bit logical address and a 28-bit physical address. Let's…

A: Multi level paging is a paging scheme which consist of two or more levels of paging tables in…

Q: Consider a paging system with the following: Physical memory= 32 bytes. Page size=4 bytes. Page…

A: Page size = 4B. So page offset = 2 bits.  The offset for physical and virtual address is same.  A)…

Q: Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main…

A: Question from cache memory mapping. In this we are talking about set-associative cache mapping. We…

Q: Consider a system where the page fault service time is 200ms, and the main memory access time is…

A: To find Effective memory access time.

Q: QUESTION 15 Given the logical address OxD953 (in hexadecimal), What is the page number and the page…

A: The given logical address is 0xD953  (in hexadecimal)                                           =…

Q: Suppose the page table for process B that is currently executed on the processor is as in Table 1.…

A: List the logical address ranges for each page.       Given the following new ordered page…

Q: b. Suppose we use two-level paging and arrange for all page tables to fit into a single page frame.…

A:

Q: Consider a paging system with the following: Physical memory= 32 bytes. Page size=4 bytes. Page…

A: First we see what is actual location and what is coherent location :-  Consistent Address - Logical…

Q: Given a scenario where there are four frames. The following table shows the loading time of a page…

A: Im providing the answer of the above question. I hope this will help..

Q: Consider a logical address of 128 pages of 1024 words each, mapped onto a physical memory of 64…

A: Hey there, I am writing the required solution based on the above given question. Please do find the…

Q: 5. Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses. a) What is the…

A: A virtual address space or address space is the set of ranges of virtual addresses that an operating…

Q: Consider a computer system with a 30-bit logical address and 4-KB page size. The system supports up…

A: Here is the answer with an explanation:-

Q: Suppose we have already the page table shown below, what happens when CPU generates address 3000?…

A: Given:

Q: Consider a system with a 7-bit virtual address space,32-byte pages and 512-byte physical memory. The…

A: In this question, we are given virtual address and physical address with page size. Virtual address…

Q: Assuming a page size of 4 Kbytes and that a page table entry takes 4 bytes, how many levels of page…

A:

Q: (a) Explain the use of TLBs to improve paging efficiency.  (b) Consider a paging system with the…

A: A). To overcome this problem a high-speed cache is set up for page table entries called a…

Q: Assume a 32-bit virtual address and 4 MBs of memory (i.e., DRAM). If the page size is 1 KB, then…

A: Assume a 32-bit virtual address and 4 MBs of memory (i.e., DRAM). If the page size is 1 KB, then…

Q: Suppose the page table for a process A currently executing on the processor looks like the…

A: This is a multipart question, we are only allowed to solve 3 parts at a time, I am solving c, d, e…

Q: Consider a computer system with a byte- addressable main memory of size 16 Gigabytes. The computer…

A: Given Memory size - 16 Gigabytes  16 Gigabytes = 17179869184 Bytes                           = 234…

Q: 1. Consider a logical address of 128 pages of 1024 words each, mapped onto a physical memory of 64…

A: The answer as given below:

Q: Consider the following portion of a page table from a system with 4 KiB (i.e., 4096 byte) pages.…

A: We have given portion of page table and page size is 4KiB. Using virtual memory address, we have to…

Q: 10.5 Consider the page table for a system with 12-bit virtual and physical addresses and 256-byte…

A: Dear Student, As we know that virtual pages consist of page number of 4bits and remaining 8bits of…

Q: Consider a paging system with the page table stored in memory. 80 percent of all page-table…

A: Here in this question we have given a paging system in which 80 % of all page table reference found…

Q: Consider a paging memory allocation whose page size is 5KB and one word is equal to 8 Bytes. Answer…

A: Total number of words in one page = 5KB/8B = 640 words.    Logical address = 33124 Page number =…

Q: Consider a system with 36-bit virtual addresses, 32-bit physical addresses, and 4KB pages. The…

A: Given,The virtual Address space = 236 bytesPage size = 212 bytesPages = 236 / 212 = 224  Pages

Q: In a page addressing system of 10 bits, where four bits are used for the page number, what would be…

A: A page is contiguous virtual memory which is smallest unit to store data in memory management…

Q: Consider a logical address space of 1K pages with a 4KB page size, mapped onto a physical memory of…

A: Below is the answer to above question. I hope this will be helpful for you..

Q: In a system, with 10 bit addresses of which 4 bits is for the page number, give following page…

A: Here number of bits for page number=4 Thus number of bits for offset = 10-4 = 6. These are least…

Q: Consider a system with 36-bit addresses that employs both segmentation and paging. Assume each PTE…

A: This is Operating system related question.

Q: Consider a system with 36-bit virtual addresses, 32-bit physical addresses, and 4KB pages. The…

A: Given,The virtual Address space = 236 bytesPage size = 212 bytesPages = 236 / 212 = 224  Pages

Q: Consider a paging system with the page table stored in memory. a. If a memory reference takes 400…

A: Since, number of memory accesses required by a paged memory reference = 2   Time taken by a memory…

Q: Suppose we have a virtual address of 26 bits in a byte addressable machine. Page size is 8K bytes.…

A: Suppose we have a virtual address of 26 bits in a byte addressable machine. Page size is 8K bytes.…

Q: A system has 4-kB pages, a 48-bit virtual address space, and a 33-bit physical address space.…

A: Lets see the solution in the next steps

Q: Exercise: A computer has 4 frames. Page size is 2KB (2048). The loaded time, the R and M bits for…

A: so we have to calculate physical address of given virtual addresses  Which is calculated Below

Q: Consider a system consisting of thirty-two bits virtual address, page size is 16 KB and a 512 lines…

A: The virtual address is of 32 bits. Whenever CPU wants any data from the memory, it  generates 32bit…

Q: A computer with 32 bits virtual address uses a two-level page table. Virtual addresses are split…

A: GIVEN: A computer with 32 bits virtual address uses a two-level page table. Virtual addresses are…

Q: Page address stream 2 3 2 1 5 4 5 3 2 5 2 4. 3 4 ОРТ 3 3 3 3 3 3. 5. 3. 5n F F 2. 235F 2. 23

A: Solve fifo , lpu, opt algorithm with example.

Q: Consider a 64-bit Logical Address Space a. Given Page size of 4 KB Find Out. Number of Page Table…

A: Solution-   Given values are- Number of bits in logical address = 64 bits Page size = 4KB Page…

Q: Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB, and a PTE…

A: Data given in the question, 32-bit address system page size of 2 KB PTE (Page Table Entry) size of 1…

Q: Given a virtual memory of size 4 GiB, physical memory of size 512 KiB, and page size equal to 4 KiB.…

A: Ans:) The higher order bits of any virtual address creates a page number while lower order bits form…

Q: Suppose we have a byte-addressable computer using a direct mapped caching with 20-bit main memory…

A: Actually, binary numbers are 1's and 0's. 1 byte =8 bits

Q: Consider a system with 64-bit address that supports multi-level page tables with two levels. The…

A: The address of a process is first divided into equal-sized pages. These pages are kept under a table…

Q: Assuming a 1 KB page size, what is the page number and offset for the address references of 111279?…

A: The above problem can be solved using formula:   Page number = logical address / page size Offset =…

Q: Consider the following example and perform complete working of paging, generate the logical and…

A: Considering the image, if the CPU demands the 2nd kb of the 3rd process for processing, then the 6th…

Q: a) In the SRAM region, what is the corresponding bit-band alias address for the bit [4] of the…

A: a) In the SRAM region, what is the corresponding bit-band alias address for the bit [4] of the…