Given the beam loaded as shown. 60 KN 3 m 50 kN/m 10 kN-m A D B 1 m 5 m
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3. What is the value of moment in Kn-m, at the location of the concentrated load 60 KN?
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- Question:- A 7.5 meters long simply supported structural steel beam carries two concentrated loads P at every third points. Use A 572 Grade 65 steel with Fy=448.18 MPa. The beam is W310x23.8 section having the given properties. A=3040mm² d= 305mm tw= 5.6mm bf=101mm tf= 6.7 mm Ix= 43x10⁶ mm⁴ Iy=1.2x10⁶mm⁴ a) Calculate the allowable bending stress of the compression flange of beam 7.5 fully supported against lateral movement. b) Based from the previous question, calculate the value of concentrated load P that the beam could support safety.A beam 9 meter long is fixed at both ends and carries a uniformly distributed load of 25 kN/m throughout its length. The beam is a wide flange section with the following properties:flange width, bf = 260 mmflange thickness, tf = 19.3 mmoverall depth, d = 420 mmweb thickness, tw = 11.6 mmstrong axis moment of inertia, Ix = 462.02 x 10^6 mm^4weak axis moment of inertia, Iy = 57.44 x 10^6 mm^4Calculate the maximum bending moment for the structure.Calculate the average web shear stress in MPa.Calculate the maximum bending stress for the beam in MPa.Calculate the maximum shearing stress in the beam in MPaCalculate the maximum shear for the beam.Calculate the minimum shearing stress in the beam in MPa.A 6.96.9 mm long simply supported wood beam carries a uniformly distributed load of 10.810.8 kN/mkN/m, as shown in Figure A. The cross-sectional dimensions of the beam as shown in Figure B are b=195b=195 mmmm, d=490d=490 mmmm, yH=80yH=80 mmmm, and yK=158yK=158 mmmm. Section a–a is located at x=1.4x=1.4 mm from B. (a) At section a–a, determine the magnitude of the shear stress in the beam at point H. (b) At section a–a, determine the magnitude of the shear stress in the beam at point K. (c) If the allowable shear stress for the wood is 950950 kPakPa, what is the largest distributed load ww that can be supported by the beam?
- A simple beam having a span of 10 m carries a dead load (including its own weight) of 6.5 kN/m. The beam is continuously braced and A992 steel. Properties: A= 9484 mm2 Ix= 333 x 10^6 mm4 d= 456.95mm Sx= 1457x10^3 bf= 190.37 mm Zx= 1655x10^3 mm3 tf= 14.48 mm What is the allowable shear strength (kN)? tw= 9.02 mmA rectangular reinforced concrete beam 350 x 550 mm (b x d) is provided with 3H25 bar (As = 1473 mm2) as compression steel. Determine the area of tension steel needed for the beam to attain its full moment capacity. Calculate the corresponding ultimate moment of resistance. Assume fck = 35 N/mm2and fyk = 500 N/mm2and d’ = 60mm. Take until 2 decimal point for each calculation. Notes : Internal forces Fcc = 0.567fck(b x 0.8x) = 0.454 fck bx Fst = 0.87 fyk As Moment of resistance with respect to steel, M = Fcc.z Moment of resistance with respect to concrete, M = Fst.z Mbal = Kbal fck bd2 where Kbal = 0.167 As ‘ = (M-Mbal) / 0.87 fyk (d-d’) As = Mbal / 0.87 fyk zbal + As’A cantilever beam, 3.5 m long, carries a concentratedload, P, at mid-lengthGiven:P = 200 kNE = 200 GPaI = 60.8 x 10^6 mm^4 How much is the deflection (mm)at mid-length What force (kN) should be applied at the free end to preventdeflection? To limit the deflection at mid-length to 9.5 mm, how much force(kN) should be applied at the free end?
- A simply-supported T-beam is subjected to two pairs of distributed loads: pair 1 (wD1, wL1)and pair 2 (wD2, wL2). The geometric, material and loading properties are all given on thetable above. bf=1368mm bw=408mm t=248mm fc'=25.2MPa fy=336MPa d=918mm d'=92mm Lbeam=12.2m wD1=42.2kn/m wL1=50.2kn/m wD2=170.2kn/m wL2=193.3kn/m1. Solve for the height of the compression stress block using pair 1. 2. Solve for the theoretical steel area using pair 1. 3. Using Es = 0.004, solve for the theoretical steel area using pair 2. 4. Using Es= 0.005, solve for the theoretical steel area using pair 2.A wide flange A992 steel column has a length of 4.6 meters and pinned ends. If Sx=895x103 mm3, Sy=129x103 mm3, d=358mm, bf=172mm, A=7226 mm2, Fy=345MPa, Determine the classification of the column.hi im stuck in this please help me out A wooden beam is loaded by a concentrated load ?P = 5000 N and supported by boundary conditions as shown in Figure Q5(a). The cross-section of the beam is shown in Figure Q5(b). Given that ???LAB = 3000 mm, ???LBC = 2000 mm, ?0B0=10 mm, ?1B1 = 30 mm, and ?H = 240 mm, ℎ0h0=200 mm, ℎ1h1=20 mm, determine the following quantities below: last two sub parts of question didnt fit in so i will type here- theres no question d e) Determine the maximum magnitude of shear force and bending moment, neglecting the sign. The maximum magnitude of internal shear force, positive value: N The maximum magnitude of internal bending moment, positive value: N*mm f) Determine the magnitude of the maximum bending stress in the beam, neglecting the sign. Maximum bending stress, positive value: MPa
- A W8x35 steel column has unsupported length of 8m. Using A36 steel, compute for the ultimate axial load capacity (in kN) if both ends are a.) PINNED b.) FIXED? Neglect local buckling. W8x35 Properties A = 6645.15mm^2 lx = 52.45 x 10^6 mm^4 ly = 17.69 x 10^6 rx = 88.9 mm ry = 51.56mmUPVOTE WILL BE GIVEN! PLEASE ANSWER ALL THE SUBQUESTIONS AND WRITE THE COMPLETE SOLUTIONS LEGIBLY. NO LONG EXPLANATION NEEDED! MULTIPLE CHOICES ONLY! For the given loaded beam, the shear force at the leftmost end of teh beam is a. 20 kN downward b. 20 kN upward c. 0 d. a distributed force with intensity equal to 20 kN/mSituation 6: A W18x97 simply supported beam carries a uniformly distributed load. The properties of the section relevant to the problem are as follow: Use A50 steel and Cb = 1.14d = 472 mmbf = 282 mmtf = 22.1 mmtw = 13.6 mmkdes=32.3 mmry = 67.3 mmlx = 728 x 10^6 mm^4ly = 83.7 x 10^6 mm^4Sx= 3080 x 10^3 mm^3Zx =3460 x 10^3 mm^3 J = 2440 x 10^3 mm^3Cw= 4240 x 10^9 mm^6 Which of the following nearly gives the Design Strength Moment (LRFD) if the span of the beam is 9 m?a) 666 kN-mb) 367 kN-mc) 781 kN-md) 381 kN-mNEED ASAP