Given the differential equation y" + 4 y' + 7y = 9 e-2 cos(3 x) %3D And the Solutions to its Characteristic Equation Characteristic Solutions: R = -2 + 3 i (1) Determine the General Form of the Particular Solution, and (2) Write the General Solution for the Particular Side of the Differential Equation. y, = [Ax + B]e-2 cos(V3x) + [Cx + D]e-2i sin(/3 x) B yp = A e-2* cos(3 x) + Be-2* sin(V3 x) Yp = A e-2 + Bе-2 D y, = Ax e-2* cos( V3 x) + Bx e-2* sin 3 x) y , = [Ax? + Bx]e-2 cos(V3 x) (3 x) + [Cx2 + Dx]e-24 sin y, = Ax e-2 + Bx e-2x

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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q17

Given the differential equation
y" + 4 y' + 7y = 9e-2 cos( 3 x)
And the Solutions to its Characteristic Equation
Characteristic Solutions: R = -2 + V3 i
(1) Determine the General Form of the Particular Solution, and (2) Write the General Solution for the Particular Side of the
Differential Equation.
A
= [Ax + B]e- cos(V3x) + [Cx + D]e=2* sin(3 x)
-2 sin(/3 x)
!!
B
y, = A e-2* cos(3x) + Be-2 sin3x)
3 х
O y, = A e-2
+ Be-2r
D y, = Ax e -2* cos( V3 x) + Bx e-2* sin( V3 x)
+ Bx e-2 sin( 3 x)
E
y, = [Ax? + Bx]e-2 cos(3 x) + [Cx? + Dx]e * sin(/3 x)
!!
F
= Ax e-2x
+ Bx e-2
Transcribed Image Text:Given the differential equation y" + 4 y' + 7y = 9e-2 cos( 3 x) And the Solutions to its Characteristic Equation Characteristic Solutions: R = -2 + V3 i (1) Determine the General Form of the Particular Solution, and (2) Write the General Solution for the Particular Side of the Differential Equation. A = [Ax + B]e- cos(V3x) + [Cx + D]e=2* sin(3 x) -2 sin(/3 x) !! B y, = A e-2* cos(3x) + Be-2 sin3x) 3 х O y, = A e-2 + Be-2r D y, = Ax e -2* cos( V3 x) + Bx e-2* sin( V3 x) + Bx e-2 sin( 3 x) E y, = [Ax? + Bx]e-2 cos(3 x) + [Cx? + Dx]e * sin(/3 x) !! F = Ax e-2x + Bx e-2
Expert Solution
Step 1

The operator method is very convenient in using the particular solution. Every linear differential equation of higher order can be expressed as FDy=fx

Suppose yp be the particular integral.

Then, 

yp=fxFD

There are many rules for different fx. For an example, when fx=eax

yp=eaxFa, Fa0

If Fa=0, then, 

yp=xeaxF'a, F'a0

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