Given the expression for the potential V= 3x-y z3 1 complete the expression below to compute for E and

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Given the expression for the potential V=
E=
P₁
0
a[B]
- [14] 018)
a[G] a[H] a[1]
+
+
əx ду дz
✓ [A]
✓ [B]
✓ [C]
✓ [D]
✓ [E]
✓ [F]
✓ [G]
✓ [H]
3x²y
-3
a[D]
-a +[C]· -a +[E]· -a
əx X
a[F]
дz
dy y
complete the expression below to compute for E and
0
Finally, by inspection, essentially is obtained by taking the negative [J] of the potential function V.
1
0²/0°
A. None of the choices
B.x2
C. 3x²y
D. 3y
E.
3x²
Transcribed Image Text:Given the expression for the potential V= E= P₁ 0 a[B] - [14] 018) a[G] a[H] a[1] + + əx ду дz ✓ [A] ✓ [B] ✓ [C] ✓ [D] ✓ [E] ✓ [F] ✓ [G] ✓ [H] 3x²y -3 a[D] -a +[C]· -a +[E]· -a əx X a[F] дz dy y complete the expression below to compute for E and 0 Finally, by inspection, essentially is obtained by taking the negative [J] of the potential function V. 1 0²/0° A. None of the choices B.x2 C. 3x²y D. 3y E. 3x²
A. None of the choices
B. x2
C. 3x²y
D. 3y
E.
z³
F. 1
3x-2
z.³
z.3
G. Divergence
H. Gradient
I. Laplacian
J. y
K. 3x2
z3
6xy
M. 9x²y
Transcribed Image Text:A. None of the choices B. x2 C. 3x²y D. 3y E. z³ F. 1 3x-2 z.³ z.3 G. Divergence H. Gradient I. Laplacian J. y K. 3x2 z3 6xy M. 9x²y
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