Given the following at 25 °C and 1.00 atm: 2Fe(s) + 02(g) → 2FEO(s) 4Fe(s) + 302(g) 2FE203(s) AH° = -1648.8 kJ AH = -544.0 kJ %3D 3Fe(s) + 202(g) Fe304(s) AH° = -1118.4 kJ Calculate the AH for the reaction below at 25 °C. Fe203(s) + FeO(s) → Fe304(s) a. -22.0 kJ O b.22.2 kJ Oc. 249.8 kJ d.-1074.0 kJ O e. 1074.0 kJ

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Chapter18: Thermodynamics And Equilibrium
Section: Chapter Questions
Problem 18.20QP: Given the following information at 25C, calculate G at 25C for the reaction 2A(g)+B(g)3C(g)...
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Given the following at 25 °C and 1.00 atm:
2Fe(s) + 02(g)→ 2FEO(s)
4Fe(s) + 302(g)→ 2FE203(s)
AH = -544.0 kJ
%3D
AH = -1648.8 kJ
3Fe(s) + 202(g) → Fe304(s)
->
AH = -1118.4 kJ
Calculate the AH for the reaction below at 25 °C.
Fe203(s) + FeO(s) → Fe304(s)
O a.-22.0 kJ
O b.22.2 kJ
Oc. 249.8 kJ
d.-1074.0 kJ
e. 1074.0 kJ
Transcribed Image Text:Given the following at 25 °C and 1.00 atm: 2Fe(s) + 02(g)→ 2FEO(s) 4Fe(s) + 302(g)→ 2FE203(s) AH = -544.0 kJ %3D AH = -1648.8 kJ 3Fe(s) + 202(g) → Fe304(s) -> AH = -1118.4 kJ Calculate the AH for the reaction below at 25 °C. Fe203(s) + FeO(s) → Fe304(s) O a.-22.0 kJ O b.22.2 kJ Oc. 249.8 kJ d.-1074.0 kJ e. 1074.0 kJ
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