Please write the value for their electrode potential: Predict the products of electrolysis of the following and write the anode reaction, the cathode reaction and the overall reaction. AGNO3(a9)\ You may refer to the following values of standard reduction potentials + 4H* (aq) + 3 e- → NO(g) + 2 H2O1) NO: (aq) E° = +0.956 V 3Ag6) 2 H2Oa) + 2 e- → H2g)+2 OH (aq) → Na(s) → K(s) Ag"(aq) + e- E° = +0.800 V E° = – 0.42 V Na* (ag) + e → E° =– 2.71 V '(aq) + e- E° = – 2.93 V

Chemistry: The Molecular Science
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Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
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Please write the value for their electrode potential:
Predict the products of electrolysis of the following and write the anode
reaction, the cathode reaction and the overall reaction.
AGNO3(a9)\
You may refer to the following values of standard reduction potentials
+ 4H* (aq) + 3 e- → NO(g) + 2 H2O1)
NO: (aq)
E° = +0.956 V
3Ag6)
2 H2Oa) + 2 e- → H2g)+2 OH (aq)
→ Na(s)
→ K(s)
Ag"(aq) + e-
E° = +0.800 V
E° = – 0.42 V
Na* (ag) + e →
E° =– 2.71 V
'(aq)
+ e-
E° = – 2.93 V
Transcribed Image Text:Please write the value for their electrode potential: Predict the products of electrolysis of the following and write the anode reaction, the cathode reaction and the overall reaction. AGNO3(a9)\ You may refer to the following values of standard reduction potentials + 4H* (aq) + 3 e- → NO(g) + 2 H2O1) NO: (aq) E° = +0.956 V 3Ag6) 2 H2Oa) + 2 e- → H2g)+2 OH (aq) → Na(s) → K(s) Ag"(aq) + e- E° = +0.800 V E° = – 0.42 V Na* (ag) + e → E° =– 2.71 V '(aq) + e- E° = – 2.93 V
2.) AGNO3 (ag) - Ag+ and NO,-
o Possible Reduction(Cathode) Half-Reaction:
E° =
Ag (s)
Ag
+ e →
(aq)
E° =
2H200 + 2e- →
+ 20H (aq)
H2 (g)
=> /Which half reaction will take place at cathode/
o Possible Oxidation(Anode) Half-Reaction:
E° =
E° =
=> /Which half reaction will take place at anode/
HALF-REACTION:
Cathode(Reduction):
Anode(Oxidation):
Overall:
The product produced at cathode:
REASON:
• The product produced at anode:
REASON:
Transcribed Image Text:2.) AGNO3 (ag) - Ag+ and NO,- o Possible Reduction(Cathode) Half-Reaction: E° = Ag (s) Ag + e → (aq) E° = 2H200 + 2e- → + 20H (aq) H2 (g) => /Which half reaction will take place at cathode/ o Possible Oxidation(Anode) Half-Reaction: E° = E° = => /Which half reaction will take place at anode/ HALF-REACTION: Cathode(Reduction): Anode(Oxidation): Overall: The product produced at cathode: REASON: • The product produced at anode: REASON:
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