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Given the following data: 4C(s) + 3H2(g) + 1/2O2(g) → HCOC(CH2)(CH3)(l)  ΔH°=-139.0 kJ CH3CH2OH(l) + 1/2O2(g) → CH3CHO(l) + H2O(l)  ΔH°=-204.0 kJ 2C(s) + 3H2(g) + 1/2O2(g) → CH3CH2OH(l)  ΔH°=-278.0 kJ H2(g) + 1/2O2(g) → H2O(l)  ΔH°=-286.0 kJ calculate ΔH° for the reaction: 2CH3CHO(l) → HCOC(CH2)(CH3)(l) + H2O(l)

Given the following data: 4C(s) + 3H2(g) + 1/2O2(g) → HCOC(CH2)(CH3)(l)  ΔH°=-139.0 kJ CH3CH2OH(l) + 1/2O2(g) → CH3CHO(l) + H2O(l)  ΔH°=-204.0 kJ 2C(s) + 3H2(g) + 1/2O2(g) → CH3CH2OH(l)  ΔH°=-278.0 kJ H2(g) + 1/2O2(g) → H2O(l)  ΔH°=-286.0 kJ calculate ΔH° for the reaction: 2CH3CHO(l) → HCOC(CH2)(CH3)(l) + H2O(l)

Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter15: Energy And Chemical Change
Section: Chapter Questions
Problem 92A
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Hess's Law



Given the following data:


4C(s) + 3H2(g) + 1/2O2(g) → HCOC(CH2)(CH3)(l)  ΔH°=-139.0 kJ
CH3CH2OH(l) + 1/2O2(g) → CH3CHO(l) + H2O(l)  ΔH°=-204.0 kJ
2C(s) + 3H2(g) + 1/2O2(g) → CH3CH2OH(l)  ΔH°=-278.0 kJ
H2(g) + 1/2O2(g) → H2O(l)  ΔH°=-286.0 kJ


calculate ΔH° for the reaction:

2CH3CHO(l) → HCOC(CH2)(CH3)(l) + H2O(l)

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