Given the following data: AH°¡[FeO(s)l = -270 kJ/mol; AH°† [Fe2O3(s)l = -820 kJ/mol. Select the expression which gives the enthalpy change, in kJ/mol, for the reaction %3D 2FEO(s) + ½02(g) -> Fe203(s) (-820 x ½) + 270= -140 -820 + (270 x 2) = -280 +820 - (270 x 2) = +280 o (+820 x 2) -270 = +140

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter7: Chemical Energy
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Given the following data: AH°¡[FeOisl = -270 kJ/mol; AH®r [Fe2O3(s)] =-820 kJ/mol.
Select the expression which gives the enthalpy change, in kJ/mol, for the reaction
2FEO(s) + ½O2(g)-> Fe203(s)
->Fe203(s)
(-820 x ½) + 270 = -140
-820 + (270 x 2) = -280
+820 - (270 x 2) = +280
(+820 x2) -270% = +140
A Moving to the next question prevents changes to this answer.
W
Transcribed Image Text:Given the following data: AH°¡[FeOisl = -270 kJ/mol; AH®r [Fe2O3(s)] =-820 kJ/mol. Select the expression which gives the enthalpy change, in kJ/mol, for the reaction 2FEO(s) + ½O2(g)-> Fe203(s) ->Fe203(s) (-820 x ½) + 270 = -140 -820 + (270 x 2) = -280 +820 - (270 x 2) = +280 (+820 x2) -270% = +140 A Moving to the next question prevents changes to this answer. W
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