Given the following data: Tinitial (°C) Tfinal (°C) H20 50.00 mL 22.46 18.32 NazS,03-5H205.10 g Calculate AH° for the reaction: NazS2O3-5H20(s) – Na,S2O3(aq) + 5H2O(I) You may assume all solutions to have the same density and specific heat as water (1.00 g/mL and 4.184 J/g°C) kJ/mol

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