Consider the combustion of liquid methanol, CH3OH1l2:CH3OH1l2 + 32O21g2¡ CO21g2 + 2 H2O1l2ΔH = -726.5 kJ(a) What is the enthalpy change for the reverse reaction?(b) Balance the forward reaction with whole-number coefficients.What is ΔH for the reaction represented by thisequation? (c) Which is more likely to be thermodynamicallyfavored, the forward reaction or the reverse reaction?(d) If the reaction were written to produce H2O1g2 insteadof H2O1l2, would you expect the magnitude of ΔH to increase,decrease, or stay the same? Explain.

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